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Novay_Z [31]
3 years ago
12

Can anyone help me with this please

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

if you need help you should be grateful they dont really need to help you

Step-by-step explanation:

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Michael, Leo and JuWoong collect stamps. The ratio of the number of Michael's stamps to JuWoong's stamps is 2:7. The number of J
Alisiya [41]

Answer:

990

Step-by-step explanation:

M/J = 2/7

J = 3/4 L

L = M + 396

7M = 2J

J = 3.5M

3.5M = 3/4 L

L = 4/3(3.5M)

L = 14/3 M

14/3 M = M + 396

11/3 M = 396

M = 3/11 × 396

M = 108

L = M + 396

L = 108 + 396

L = 504

J = 3/4 L

J = 3/4 × 504

J = 378

M + L + J = 108 + 504 + 378 = 990

4 0
3 years ago
Use slopes to determine if the lines y= -x/3- 9 and 6x – 2y = -5 are perpendicular.
WARRIOR [948]

Answer:

They are perpendicular.

Step-by-step explanation:

When we convert the equation 6x-2y=-5 into y=mx+b form, it changes into y=3x-5/2. Since we know that perpendicular slopes are opposite reciprocal, the opposite reciprocal of -x/3 is 3. So, we know that these 2 slopes are perpendicular.

8 0
4 years ago
I need help on this aswell
Katena32 [7]

Answer:

Graph C

Step-by-step explanation:

Hi there!

The given linear equations are organized in slope-intercept form: y=mx+b where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept, or the value of y when the line crosses the y-axis.

y = 2x + 4

Here, the <em>b</em> value is 4. Therefore, the y-intercept of this line is 4.

y = -3x - 2

Here, the <em>b</em> value is -2. Therefore, the y-intercept of this line is -2.

To identify the graph that models these equations, we just have to look for the graph where the lines cross the y-axis at 4 and -2.

The only graph that does this is graph C.

I hope this helps!

8 0
3 years ago
Which equation is equivalent to 3[x+3(4x-5)]=15x-24
Klio2033 [76]
3[x+3(4x-5)]=15x-24; x+12x-15=5x-8 (divide both sides by 3); 8x=7 (move all the x's to one side), x=7/8
7 0
4 years ago
Read 2 more answers
judy got 117 problems right on a math test in her night school class. She got a score of 78% right. How many problems were on th
scZoUnD [109]
You would set this up as Part÷Whole=Percent÷100
Part=117
Whole= X
Percent=78
117÷X=78÷100
Set these up as fractions and cross multiply. You will get 117×100=78X
117×100=11,700
Divide both sides by 78 and you get x=150
There were 150 problems
6 0
3 years ago
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