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Slav-nsk [51]
3 years ago
13

An insurance firm reported that "the typical water-skiing accident occurs near the dock from which they start." Which of the fol

lowing statistical measurements are they most likely discussing? A. median B. mode C. mean D. range
Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0

Answer: D. range

Step-by-step explanation:

To measure the center of the tendency we use Mean , median or mode depends on the type of data.

But when we discuss about the distance between the initial point and the final point in a data , we use 'range' as term for this.

Range= distance between initial and final point.

here, range = distance between the starting point and the point where water-skiing accident occurs.

Hence, the correct option is D. range

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y=x

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When y=x, then the line goes up 1 and right 1.

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5 times 8/7 FOR MAtH
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Answer:

40/7  =   5 5/7

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What is the sum of 1/9, 2/3,and 5/18? A.19/18 B.8/30 C.4/15 D.12/9
amm1812
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2/3 times 6/6=12/18

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8 0
3 years ago
A type of sampling in which individuals to be interviewed are selected based on their proportion or quota in the general populat
Butoxors [25]

A type of sampling in which individuals to be interviewed are selected based on their proportion or quota in the general population being polled is known as public opinion.

What is sampling type of public opinion ?

A survey that measures the entire target population is called a census. A sample refers to a group or section of a population from which information is to be obtained. Survey samples can be broadly divided into two types: probability samples and super samples.

The collective opinion of large segment of the population on an issue, candidate or public policy on which the public may be much divided and lake a consensus.

Learn more about the public opinion is here :

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2 years ago
Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1
lana [24]

We assume that the function is as follows:

f^{-1_{}}(2)=?

Then, we have that:

f^{-1}(x)=\frac{1}{f(x)}

Thus, if we have that:

f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}

Therefore, the value for the function is f^-1(2) = -1/2 or

f^{-1}(2)=-\frac{1}{2}

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10 months ago
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