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3 years ago

A dust particle weighs 7.42 x10

Mathematics

2 answers:

kogti [31]3 years ago

4 0

Answer:

how to answer this actually

Step-by-step explanation:

btw my answer is 704.2

marusya05 [52]3 years ago

3 0

Answer:

Uh, no actual question

Step-by-step explanation:

7.42x10=74.2

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Ranger simplified this expression. 3(2.7x + 5) – 2(4x – 1.6) What was Ranger's simplified expression? 0.1x + 18.2 –16.1x + 11.8

Ymorist [56]

Answer:

Ranger's simplified expression was 0.1x + 18.2

The correct answer is the first option.

Step-by-step explanation:

To simplify the given expression

3(2.7x + 5) – 2(4x – 1.6)

First, we will open the brackets by distributing 3 and 2, that is

(3×2.7x) + (3×5) -(2×4x) -(2×-1.6)

Now, we will get

8.1x + 15 - 8x +3.2

Now, collect like terms,

8.1x - 8x + 15 + 3.2

Then, we will get

0.1x + 18.2.

Hence, Ranger's simplified expression was 0.1x + 18.2.

The correct answer is the first option.

5 0

3 years ago

Read 2 more answers

9 x (-3) + (-15) ÷ 3

Galina-37 [17]

Answer:

-32

Step-by-step explanation:

9(-3) + (-15) ÷ 3 =

-27 + -5 = -32

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0

3 years ago

Read 2 more answers

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago

Hi can anyone help me pls, thx.

MrMuchimi

Answer:

24,28,32,36,40,.....

Step-by-step explanation:

It’s multiples of 4

8 0

3 years ago

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A track and field playing area is in the shape of a rectangle with semicircles at each end. See the figure. The inside perimeter

Schach [20]

Answer:

Step-by-step explanation:

Let x be the track straights lengths

Let y be the track ends diameter and the other rectangle side lengths.

1800 = 2x + πy

y = (1800 - 2x) / π

A = xy

A = x((1800 - 2x) / π

A = (1/π)(1800x - 2x²)

dA/dx = (1/π)(1800 - 4x)

0 = (1/π)(1800 - 4x)

0 = 1800 - 4x

4x = 1800

x = 450 m

y = (1800 - 2(450)) / π

y = 900/π or approximately 286.5 m

8 0

3 years ago