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2 years ago

A track and field playing area is in the shape of a rectangle with semicircles at each end. See the figure. The inside perimeter

Mathematics

1 answer:

Schach [20]2 years ago

8 0

Answer:

Step-by-step explanation:

Let x be the track straights lengths

Let y be the track ends diameter and the other rectangle side lengths.

1800 = 2x + πy

y = (1800 - 2x) / π

A = xy

A = x((1800 - 2x) / π

A = (1/π)(1800x - 2x²)

dA/dx = (1/π)(1800 - 4x)

0 = (1/π)(1800 - 4x)

0 = 1800 - 4x

4x = 1800

x = 450 m

y = (1800 - 2(450)) / π

y = 900/π or approximately 286.5 m

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Professor Harris is teaching a continuing education class at the local community college. He created the following box plot from

inessss [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:

Goshia [24]

Answer:

case 1 = 2592

case 2 = 729

case 1 + case 2 = 2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0

3 years ago

If Fun Reads Bookstore has a ready club with a $40 fee and charges $5 per book and Cool Covers Bookstores club charges $100 fee

choli [55]

Answer:

You have to buy more than 20 books to make Cool Cover Bookstore club a better deal.

Step-by-step explanation:

Given that:

Fee charged by Fun Reads Bookstore = $40

Charges per book = $5

Let x be the number of books.

A(x) = 5x+40

Fee charged by Cool Covers Bookstore = $100

Charges per book = $2

B(x) = 2x+100

For making Cool Cover Bookstores club a better deal,

B(x) > A(x)

2x+100 > 5x+40

2x-5x > 40-100

-3x > -60

Dividing both sides by -3

$\frac{-3x}{-3}>\frac{-60}{-3}\\x>20$

Hence,

You have to buy more than 20 books to make Cool Cover Bookstore club a better deal.

8 0

3 years ago

Gavin and his three friends want to share 1/3of cake equally. Gavin says that each friend will get 1/9 of the cake. Use the drop

Alexxandr [17]

Answer: Incorrect

Step-by-step explanation:

Given

Gavin and his three friends wants to share $\frac{1}{3}$ of cake equally.

So, there are 4 members to distribute the cake

Each member will get

$\Rightarrow \dfrac{\dfrac{1}{3}}{4}\\\\\Rightarrow \dfrac{1}{3\times 4}=\dfrac{1}{12}$

So, each member get one-twelvefth of the given cake.

Hence, Gavin is incorrect.

6 0

3 years ago

Read 2 more answers

Rearrange the equation so a is the independent variable.<br><br> 3a-7= -4b+1<br><br> Please help! :)

Aleksandr-060686 [28]

Answer:

Hiii the answer would be a= -4b+8/3

7 0

3 years ago