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prisoha [69]
3 years ago
13

A track and field playing area is in the shape of a rectangle with semicircles at each end. See the figure. The inside perimeter

Mathematics
1 answer:
Schach [20]3 years ago
8 0

Answer:

Step-by-step explanation:

Let x be the track straights lengths

Let y be the track ends diameter and the other rectangle side lengths.

1800 = 2x + πy

y = (1800 - 2x) / π

A = xy

A = x((1800 - 2x) / π

A = (1/π)(1800x - 2x²)

dA/dx = (1/π)(1800 - 4x)

       0 = (1/π)(1800 - 4x)

       0 = 1800 - 4x

     4x = 1800

        x = 450 m

        y = (1800 - 2(450)) / π

        y = 900/π or approximately 286.5 m

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3 0
3 years ago
Read 2 more answers
Part A:
PIT_PIT [208]

Answer:

∠ MON = 128°

Step-by-step explanation:

∠ LOM + ∠MON = ∠ LON , substitute values

3x + 43 + 8x + 104 = 180, that is

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11x = 33 ( divide both sides by 11 )

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∠ MON = 8x + 104 = 8(3) + 104 = 24 + 104 = 128°

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Answer:

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