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3 years ago

A track and field playing area is in the shape of a rectangle with semicircles at each end. See the figure. The inside perimeter

Mathematics

1 answer:

Schach [20]3 years ago

8 0

Answer:

Step-by-step explanation:

Let x be the track straights lengths

Let y be the track ends diameter and the other rectangle side lengths.

1800 = 2x + πy

y = (1800 - 2x) / π

A = xy

A = x((1800 - 2x) / π

A = (1/π)(1800x - 2x²)

dA/dx = (1/π)(1800 - 4x)

0 = (1/π)(1800 - 4x)

0 = 1800 - 4x

4x = 1800

x = 450 m

y = (1800 - 2(450)) / π

y = 900/π or approximately 286.5 m

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*there is a picture* how do you solve this? Explain please!

emmasim [6.3K]

350 more compact car spaces are available

2/5 = 0.4 = 40%
40% of 1,000 is 400
400 spots are for compact cars

On Tuesday tner were 150
So there is 350. more spots available 400-150 = 350

4 0

3 years ago

Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05

exis [7]

we are given

$f(x)=\frac{x^2-5x}{x^2-x-20}$

Firstly, we will simplify it

$f(x)=\frac{x(x-5)}{(x-5)(x+4)}$

$f(x)=\frac{x}{(x+4)}$

At x=5.5:

we can plug x=5.5

$f(5.5)=\frac{5.5}{(5.5+4)}$

$f(5.5)=0.578947$

At x=5.1:

we can plug x=5.1

$f(5.1)=\frac{5.1}{(5.1+4)}$

$f(5.1)=0.56043956$

At x=5.05:

we can plug x=5.05

$f(5.05)=\frac{5.05}{(5.05+4)}$

$f(5.05)=0.558011$

At x=5.01:

we can plug x=5.01

$f(5.01)=\frac{5.01}{(5.01+4)}$

$f(5.01)=0.5560488$

At x=5.005:

we can plug x=5.005

$f(5.005)=\frac{5.005}{(5.005+4)}$

$f(5.005)=0.5558023$

At x=5.001:

we can plug x=5.001

$f(5.001)=\frac{5.001}{(5.001+4)}$

$f(5.001)=0.5556049$

At x=4.9:

we can plug x=4.9

$f(4.9)=\frac{4.9}{(4.9+4)}$

$f(4.9)=0.5505617$

At x=4.95:

we can plug x=4.95

$f(4.95)=\frac{4.95}{(4.95+4)}$

$f(4.95)=0.5530726$

At x=4.99:

we can plug x=4.99

$f(4.99)=\frac{4.99}{(4.99+4)}$

$f(4.99)=0.55506117$

At x=4.995:

we can plug x=4.995

$f(4.995)=\frac{4.995}{(4.995+4)}$

$f(4.995)=0.55503085$

At x=4.999:

we can plug x=4.999

$f(4.999)=\frac{4.999}{(4.999+4)}$

$f(4.999)=0.55550616$

7 0

4 years ago

NEED HELP ASAP PLZ!!

Kisachek [45]

Your answer is (x-8) (x-6)

8 0

4 years ago

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I need help in this!

Nadusha1986 [10]

Answer:

Hey Dear

Graph is coinciding with (-2,-1) and (1,2)

Range = [-1,2]

7 0

3 years ago

What is the circumference and area of this circle? (Use 3.14 for pi)

vova2212 [387]

Answer:

100.531km

Step-by-step explanation:

8 0

3 years ago

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