A track and field playing area is in the shape of a rectangle with semicircles at each end. See the figure. The inside perimeter
1 answer:
Answer:
Step-by-step explanation:
Let x be the track straights lengths
Let y be the track ends diameter and the other rectangle side lengths.
1800 = 2x + πy
y = (1800 - 2x) / π
A = xy
A = x((1800 - 2x) / π
A = (1/π)(1800x - 2x²)
dA/dx = (1/π)(1800 - 4x)
0 = (1/π)(1800 - 4x)
0 = 1800 - 4x
4x = 1800
x = 450 m
y = (1800 - 2(450)) / π
y = 900/π or approximately 286.5 m
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Answer:
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TT = 3.14
The answer is 37.68 if TT is 3.14
Answer:
A is the correct answer
have a great day
Hmmm this is a little hard I believe c
