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Kipish [7]
3 years ago
9

CAN SOMEONE HELP WITH THESE 2 questions please!! Reposting cause someone said too !!! Will mark u brainlist and give u points!!!

Mathematics
1 answer:
swat323 years ago
8 0

Answer:

do u need help with the whole page?

Step-by-step explanation:

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Find the product (3a4+4)2​
asambeis [7]

The result is

9

a

2

−

16

The reason is the following:

The problem is an example of a notable product: "the sum multiplied by the diference is equal to the difference of squares", that is to say:

(

a

+

b

)

⋅

(

a

−

b

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=

a

2

−

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2

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By applying this to our question, we obtain that:

(

3

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−

4

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⋅

(

3

a

+

4

)

=

(

3

a

)

2

−

(

4

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2

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9

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2

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16

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4 0
4 years ago
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Probablitity question please fully explain answer or i will report
dsp73

Answer:

Since there is only 1/5 that is the amounts of fives so it would be 1/5 divided = 0.2 times 3 = 0.6 so 0.6 is the answer

I’m really sorry if I’m wrong ...

8 0
3 years ago
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Last Saturday, the average temperature was 8% higher than the average temperature, 2 Sundays ago, the average temperature 2 Sund
Roman55 [17]

Answer: 1.08T and (1+8/100)T

Step-by-step explanation:

Given: The average temperature two Sundays ago was T degrees Celsius.

Since, last Sunday, the average temperature was 8% higher than the average temperature two Sundays ago.

⇒ The average temperature last Sunday

Since 8%=0.08

Therefore, The average temperature last Sunday

⇒ The average temperature last Sunday

⇒ The average temperature last Sunday

⇒ The average temperature last Sunday

Thus, the right option is 1.08T and (1+8/100)T

4 0
3 years ago
The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

       y₁ = y₂

4 - 4x² = 0

        x = ±1

Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

6 0
2 years ago
Select ALL the ratios that are equivalent to 16 : 6<br>32:12<br>8:3 <br>3:8 <br>4:2​
LuckyWell [14K]

Answer:

32:12

8:3

Step-by-step explanation:

If you multiply both sides of 16:6 you'll get 32:12

If you divide both side of 16:6 by 2 you'll get 8:3

The same thing needs to be done to both sides to make the ratio equivalent

7 0
3 years ago
Read 2 more answers
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