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frozen [14]
3 years ago
8

How do I find the area of this?

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

Step-by-step explanation:

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6 in<br> 4 in<br> 4 in.<br> What is the surface area of the right square pyramid?
kondor19780726 [428]

Answer:

48in

Step-by-step explanation:

6 x 4 x 4

96

divide it by 2

48

8 0
3 years ago
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Write 6^3 in standard form
irina [24]

Answer:

216

Step-by-step explanation:

6^3 = 6 * 6 * 6

      = 216

Please mark for Brainliest!! :D Thanks!!

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3 0
3 years ago
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H(x) = x + 1 k(x) = x - 2 (h + k)(2) =​
barxatty [35]

h(x) = x + 1

k(x) = x - 2

_________________________________

(h + k)(x) = h(x) + k(x)

(h + k)(x) = (x + 1) + (x - 2) \\

(h + k)(x) = x + 1 + x - 2

(h + k)(x) = 2x - 1

(h + k)(2) = 2(2) - 1

(h + k)(2) = 4 - 1

(h + k)(2) = 3

_________________________________

And we're done.....♥️♥️♥️♥️♥️

4 0
3 years ago
In the division problem, what does the 8 represent in the quotient?<br> 3653÷13=281
yan [13]

Answer:

The eight represents a tenth/ten

Step-by-step explanation:

The 2 represents a two hundred, the 8 a eight tenth/eighty and the 1 a one

5 0
3 years ago
Find the perimeter of a regular heptagon with consecutive vertices at "A" (-2,-5) and "B" (1,-9)
weqwewe [10]

Answer:

Perimeter is 35 units.

Step-by-step explanation:

A heptagon has 7 equal sides.

Given the length of two consecutive vertices, A(-2-5) and B(1,-9).

We can find the length of AB and multiply by 7.

Recall the distance formula;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

|AB|=\sqrt{(-2-1)^2+(-5--9)^2}

|AB|=\sqrt{(-3)^2+(4)^2}

\Rightarrow |AB|=\sqrt{9+16}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5\:units

Therefore the perimeter is 7\times 5=35\:units.

7 0
4 years ago
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