Answer:
I don't know about 4 but of no. 6, it is A
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange x + 5y = 10 into this form
Subtract x from both sides
5y = - x + 10 ( divide all terms by 5 )
y = -
x +2 ← in slope- intercept form
with slope m = - 
• Parallel lines have equal slopes, hence
y = -
x + c ← is the partial equation of the parallel line
To find c substitute (1, 3) into the partial equation
3 = -
+ c ⇒ c = 
y = -
x +
← equation of parallel line
Answer: see below
Step-by-step explanation:
(i)
200/2 = 100
Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.
(ii)
First, find the lower quartile —> 200/4 = 50
Upper quartile —> 200/(3/4) = 150
Find the difference: 150 - 50 = 100
So the interquartile range is 100
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Answer: The answer is x^2 + 4x - 3
Step-by-step explanation:
You just combine like terms, the only ones that can combine is the 6x and -4x. You just subtract them to get the answer of x^2 + 4x - 3.
Answer:
answer = 12.87 km/h
Step-by-step explanation:
Given
Ship A is sailing east at 25 km/h = 
ship B is sailing north at 20 km/h =
here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively
so we get x = 4 ×25 =100 km/h
y = 4× 20 = 80 km/h
let z is the distance between the ships, we need to find
at t = 4 hr
At noon, ship A is 130 km west of ship B (12:00 pm)
so equation will be


derivative first equation w . r. to t we get



![\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]](https://tex.z-dn.net/?f=%5Cfrac%7Bdz%7D%7Bdt%7D%20%3D%5Cfrac%7B1%7D%7Bz%7D%5B%28x%20-130%29%5Cfrac%7Bdx%7D%7Bdt%7D%20%2By%5Cfrac%7Bdy%7D%7Bdt%7D%5D)

