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4 years ago

8

Name a muscle found in the cat but absent in the human that can extend the forelimb

1 answer:

DaniilM [7]4 years ago

8 0

Answer: xiphihumeralis

Xiphihumeralis muscle is a thin tendon-like band of muscle<span> which runs lateral from the smaller pectoral muscle and inserts thru e proximal end of the humerus (arm bone) of a cat. It is the fourth muscle of the pectoralis group. It assists<span> pectoralis minor and moves/ extend the arms/forelimbs. </span></span>

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Fill in the missing mRNA and the amino acid sequence that corresponds to the DNA base

lukranit [14]

I don't know what the sequence is, but here's what you need to know in order to transcribe them.

A matches with U

T matches with A

G matches with C

C matches with G

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3 years ago

The bacteria cell cycle does not have an analogous phase to the eukaryotic phase G2. The reason for this is that _____.

eimsori [14]

Answer:

At the same time, chromosome replication and partitioning take place.

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Pseudomonas putida is used for fermentation of the lactose present in cheese whey. The bacteria are cultivated in a steady-state

fgiga [73]

Answer:

Explanation:

Given that:

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Also;

$Y_{X/S} = 0.45 g\ X/g \ S , \\ \\ Y_{X/O2 }= 0.25 g \ X/g \ O2, \\ \\$

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To calculate the steady-state biomass, we use the formula:

$X = Y_{X/S}(S_o-S_e) \\ \\ X = 0.45(2.0 -0.10) \ g/L \\ \\ X= 0.45 (1.9) \ g/L \\ \\ X = 0.855\ g/L \\ \\ X = 855 \ mg/L$

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For a steady-state condition, the oxygen uptake rate can be illustrated by using the formula:

$q_{o_2}X =\dfrac{\mu_X}{Y_{X/O_2}}$

where;

$\mu =$ dilution rate (D)

Thus, the steady-state can be expressed as:

$q_{o_2}X =\dfrac{D}{Y_{X/O_2}}$

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In the fermentation medium, if the desired DO concentration $C_L$ = 2 mg/L

Here, the oxygen transfer is regarded as the rate-limiting step.

As such, the oxygen transfer rate(OTR) is equivalent to the oxygen uptake rate.

In this scenario, let's determine the oxygen transfer coefficient $(K_{La})$ by using the formula:

$OTR = K_{La}(C^* - C_L)$

where;

$K_{La}$ = coefficient of oxygen transfer

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Since $OTR = q_{O_2}X$

$q_{o2}X = K_{La}(C^*-C_L) \\\\ (1.12 )(855) = K_{La}(8-2) \\ \\ 957.6 = K_La (6) \\ \\ K_{La}= \dfrac{957.6}{6} \\ \\ K_{La} = 159.6 \ h^{-1}$

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