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2 years ago

4x^2-6x+2=0 plssssssssss

Mathematics

1 answer:

fomenos2 years ago

7 0

Answer:

x1 = 1 x2= 1/2

Step-by-step explanation:

DELTA= b^2-4*a*c

DELTA=(-6)^2-4*4*2= 4 >0 ==> 2 solutions

x1 = (-b+sqrtDELTA)/2*a = (6+2)/2*4 = 1

x2 = (-b-sqrtDELTA)/2*a = (6-2)/2*4 = 1/2

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What roles did militias play in the American Revolution? Your answer:

Annette [7]

Hey there! I'm happy to help!

A militia is a local army. During the Battle of Lexington and Concord, the local militia (called minutemen), the militia outnumbered the British at Concord and chased them all the way back to Boston. The militia aided in many American victories during the Revolutionary War.

I hope that this helps! Have a wonderful day! :D

8 0

2 years ago

Solve the reciprocal <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%7D%20" id="TexFormula1" title=" \frac{1}{x} " al

swat32

Answer:

the reciprocal is just x because x over 1 is just x

Step-by-step explanation:

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7 0

1 year ago

a student must have an average on five test that is greater than it equal to 80% but less than 90% to receive a final grade of B

Bad White [126]

Answer:

89–100

Step-by-step explanation:

Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...

80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90

Multiplying by 5 gives

400 ≤ 311 +x ≤ 450

Subtracting 311 gives the range for the fifth test grade.

89 ≤ x ≤ 139

Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...

89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test

6 0

3 years ago

Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculato

Mariulka [41]

The mean of the dataset is the average, while the median is the middle element.

The mean and the median of the given dataset is 98.2
The results support the common belief that the mean body temperature is 98.6F

The mean of the dataset is calculated using:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{99.2+ 99.2 +98.2+............+97.7}{48}$

$\bar x = \frac{4715}{48}$

$\bar x = 98.2$

The median position is:

$Median = \frac{1}{2}(n + 1)$

$Median = \frac{1}{2}(48 + 1)$

$Median = \frac{1}{2}(49)$

$Median = 24.5$

This means that the median is the average of the 24th and 25th element

Using the sorted dataset, we have:

$Median = \frac{1}{2}(98.2 + 98.2)$

$Median = 98.2$

Because the calculated mean and the common belief (98.6) are close, then we can conclude that the results support the common belief that the mean body temperature is 98.6F