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3 years ago

HELP ME PLEASEEEEEEEEEEEEEEEEE

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

Answer:

Well if i am completely correct that means the same as median so im gonna go with 8.Good luck tho

spin [16.1K]3 years ago

5 0

Second quartile is another name for median, so the answer is 8. I think. I'm second guessing myself now..

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Change the equation of the circle x^2+14x+y^2-10y=14x 2 + 14 x + y 2 − 10 y = 14 into center-radius form of a circle.

jonny [76]

Answer:

The answer to your question is (x + 7)² + (y - 5)² = 88

Step-by-step explanation:

Equation

x² + 14x + y² - 10y = 14

Complete perfect trinomial squares

x² + 14x + (7)² + y² - 10y + (5)² = 14 + (7)² + (5)²

Simplify

x² + 14x + (7)² + y² - 10y + (5)² = 14 + 49 + 25

x² + 14x + (7)² + y² - 10y + (5)² = 88

Factor

(x + 7)² + (y - 5)² = 88 This is the equation in the form

center-radius

7 0

3 years ago

50(1.05)t < 100 how much growth or decay

makvit [3.9K]

$50(1.05)t \ \textless \ 100$

3 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Help with question B please <br> No scam brainliest will be given

erma4kov [3.2K]

Are you still looking for a answer? If so I would love to give you mine.

4 0

3 years ago

Find the value for x and y for the triangle. Show work.

HACTEHA [7]

Answer:x= 8/√3, y= 16/ √3

Step-by-step explanation:

See the picture below

4 0

2 years ago