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nirvana33 [79]
2 years ago
12

Can someone please help

Mathematics
2 answers:
mel-nik [20]2 years ago
7 0

Answer:

it is (4, 1.5)

Step-by-step explanation:

add the x-axis's together then half it then keep that x-axis, then add the y-axis's together then half it then keep that y-axis. Then you have your answer.

anzhelika [568]2 years ago
4 0
the initial value is (4, 1.5)
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The diagram shows a rhombus inside a regular hexagon work out the angle x
kvv77 [185]

Answer:

<u>x = 60°</u>

Step-by-step explanation:

The rest of the question is the attached figure.

And it is required to find the angle x.

As shown, a rhombus inside a regular hexagon.

The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°

So, the measure of one angle of the regular hexagon = 720/6 = 120°

The rhombus have 2 obtuse angles and 2 acute angles.

one of the obtuse angles of the rhombus is the same angle of the regular hexagon.

So, the measure of each acute angle of the rhombus = 180 - 120 = 60°

So, the measure of each acute angle of the rhombus + the measure of angle x = the measure of one angle of the regular hexagon.

So,

60 + x = 120

x = 120 - 60 = 60°

<u>So, the measure of the angle x = 60°</u>

6 0
3 years ago
How will the volume of the pyramid change if each side is multiplied by a factor of .5
kupik [55]
It will expand. Or it will grow.
3 0
3 years ago
The radius of a sphere is 12 units. Find the volume of the sphere. Write your answer in terms of pi.
stiv31 [10]

Answer:

V = 2304π units³

Step-by-step explanation:

The volume (V) of a sphere is calculated as

V = \frac{4}{3}πr³ ( where r is the radius ) , then

V = \frac{4}{3}π × 12³

   = \frac{4}{3} π × 1728

   = 4π × 576

   = 2304π units³

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%206x%2B4y-2x" id="TexFormula1" title="\sf 6x+4y-2x" alt="\sf 6x+4y-2x" align="absmiddle"
tangare [24]
Not sure what form you want this in:

Simplified this is 4x+4y

Factorised this is 4(x+y)

3 0
2 years ago
Read 2 more answers
Suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 i
ch4aika [34]
Mean = 62 in
SD = 2 in

At 16% = 0.16 and using Z tables,

Z≈ -0.99

x =(-0.99*2) + 62 ≈ 60 in

This represents jockeys who are shorter than 60 in.
6 0
3 years ago
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