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2 years ago

13

Pls, help due in 10 mins! Pls, answer both questions!

1 answer:

vredina [299]2 years ago

5 0

Answer:

Answer for first question is 22 yards!

Step-by-step explanation:

I used to do this, you have to multiply. A way of helping, is to split it in half, then add it all together. Now, I am not always accurate but I hope this helps you!

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Make x the subject 4x=y

Mandarinka [93]

Answer:

x=y/4

Step-by-step explanation:

Simply divide by 4 to get x by itself

3 0

3 years ago

2. Factorise: a - b - a + b2.square

marshall27 [118]

A - a removes both a’s from equation, then you’re left with b + bsquared, since they are unknown values you cannot combine them, even if it is the same letter, you can only add and subtract unknown values with their same letters together.

7 0

2 years ago

Two interior angles of a scalene triangle measure 85 and 50 degrees. The third angle measures:

zmey [24]

The interior of a triangle = 180°
So 180° - 85° -50° = 45°

c. 45 degrees

3 0

3 years ago

Please help will give 10 points!!!

AlexFokin [52]

Answer:

m = variables

+4 = Coefficients

-7 = Coefficients

and 2 and 6 are Constants

Hope this helps!

Step-by-step explanation:

4 0

2 years ago

For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10

professor190 [17]

The true statements are:

Tyson's expression is not equivalent to the original expression
The equivalent expression is: $\frac{1}{2}g- \frac 1{5}$

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}$

Collect like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10} -\frac{1}{10}$

Evaluate the like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}$

Tyler's equivalent expression is given as:

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}$

Collect like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}$

Evaluate the like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g$

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0

2 years ago