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Naya [18.7K]
3 years ago
7

kayla bought h number of hats for $13.25 each.if she has $50 dollars to spend ,how many hats could she have bought?

Mathematics
1 answer:
shutvik [7]3 years ago
7 0
4 is the answer to your question
You might be interested in
Probability of rolling a 6 with two dice one with values 1, 2, 2, 3, 3, 4 and 1, 3, 4, 5, 6, 8
777dan777 [17]

Answer:

11/12 chance of the probability of rolling a 6 with 2 dice

8 0
1 year ago
What are the solutions to this quadratic equation? x2+6x-5 A. B. C. D.
faltersainse [42]
Factoring x2-6x+5

The first term is, x2 its coefficient is 1 .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is +5

Step-1 : Multiply the coefficient of the first term by the constant 1 • 5 = 5

Step-2 : Find two factors of 5 whose sum equals the coefficient of the middle term, which is -6 .

-5 + -1 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and -1
x2 - 5x - 1x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-5)
Add up the last 2 terms, pulling out common factors :
1 • (x-5)
Step-5 : Add up the four terms of step 4 :
(x-1) • (x-5)
Which is the desired factorization

Equation at the end of step
1
:

(x - 1) • (x - 5) = 0
STEP
2
:
Theory - Roots of a product

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

2.2 Solve : x-1 = 0

Add 1 to both sides of the equation :
x = 1

Solving a Single Variable Equation:

2.3 Solve : x-5 = 0

Add 5 to both sides of the equation :
x = 5

Supplement : Solving Quadratic Equation Directly

Solving x2-6x+5 = 0 directly
Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

3.1 Find the Vertex of y = x2-6x+5

Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 3.0000

Plugging into the parabola formula 3.0000 for x we can calculate the y -coordinate :
y = 1.0 * 3.00 * 3.00 - 6.0 * 3.00 + 5.0
or y = -4.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2-6x+5
Axis of Symmetry (dashed) {x}={ 3.00}
Vertex at {x,y} = { 3.00,-4.00}
x -Intercepts (Roots) :
Root 1 at {x,y} = { 1.00, 0.00}
Root 2 at {x,y} = { 5.00, 0.00}
4 0
2 years ago
4x+2y=18, 5x+4y=13<br> what is the value of x and y
MrRa [10]

Here you go hope it helps

8 0
2 years ago
Write the slip-intercept form of the equation of the line described
kompoz [17]

Answer:

1) y=⅚x -2⅓

2) y=8/3x -5

Step-by-step explanation:

<u>Point-slope form:</u>

y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient.

Gradient of given line= \frac{5}{6}

Thus, m=⅚

Susbt. m=⅚ into the equation,

y= ⅚x +c

Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.

When x=4, y=1,

1= ⅚(4) +c

1 =  \frac{20}{6}  + c \\ c = 1 -  \frac{20}{6}  \\ c = 1 - 3 \frac{1}{3}  \\ c =  - 2 \frac{1}{3}

Thus the equation of the line is y =  \frac{5}{6} x - 2 \frac{1}{3}.

The gradients of perpendicular lines= -1.

Gradient of given line= -⅜

-⅜(gradient of line)= -1

gradient of line

= -1 ÷ (-⅜)

= -1 ×(-8/3)

= \frac{8}{3}

y =  \frac{8}{3} x + c

When x=3, y=3,

3 =  \frac{8}{3} (3) + c \\ 3 = 8 + c \\ c = 3 - 8 \\ c =  - 5

Thus the equation of the line is y =  \frac{8}{3} x - 5.

4 0
3 years ago
2x+3y=15<br> x+y=6<br> work out the values of x and y
Anna [14]

Answer:

x=3

y=3

Step-by-step explanation:

x = 6-y

-plug in (6-y) into first equation

2(6-y)+3y = 15

12-2y+3y=15

-2y+3y = 3

y=3

x=6-3

x=3

double check:

(2*3) + (3*3) = 6 + 9 = 15

3 + 3 = 6

6 0
3 years ago
Read 2 more answers
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