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KatRina [158]
3 years ago
12

What is the following product

Mathematics
1 answer:
marta [7]3 years ago
3 0

Answer:

download photomath for problems like these

You might be interested in
Select two choices that are true about the function f(x)=23x+14/x
WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0
3 years ago
Below are monthly rents paid by 30 students who live off campus.
Hatshy [7]
What is the question
6 0
1 year ago
Luigi is an urban planner. As an independent contractor, he charges a $140 fee plus $25 per hour for
Anuta_ua [19.1K]

Answer:

Function: y=140+25x

Amount earned for 10 hours of work: \$390

Step-by-step explanation:

Let be "x"  the number of hours worked on a project and "y" the total amount Luigi charges for a project.

Based on the data given in the exercise, you can identify that:

  • $140 is a fixed amount.
  • For each hour worked on the project, Luigi charges $25. This can be expressed as: 25x

Then, the total amount he charges for a project is the sum of $140 and 25x. This can be represented with the following function:

y=140+25x

To calculate the amount of money earned for 10 hours of work, you must substitute x=10 into the function and evaluate. Then:

y=140+25(10)\\\\y=390

7 0
3 years ago
13.27= t - 24.45 show your work
Irina18 [472]
Subtract 24.45 from itself the subtract 13.27 by 24.45 and should t=37.73
7 0
3 years ago
Find all 6 trig functions given the terminal side goes through point (0,-3)
d1i1m1o1n [39]
So hmm notice the picture below

that's (0, -3)

now, keep in mind, adjacent is 0, opposite is -3, and hypotenuse, or radius, is 3

and recall  sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\ \quad \\

% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

8 0
3 years ago
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