3 years ago

If h(x)=x2-5+7. h(2)

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1 answer:

3 0

The way to solve this is by re-writing the equation except with 2 as x.
h(x)= x^2-5+7
h(2)= 2^2-5+7
h(2)=4-5+7
h(2)=-1+7
h(2)= 6

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