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LuckyWell [14K]
3 years ago
5

Find the volume of a rectangular pyramid, with a height of 12 cm, length of 8 cm, and a width of 6cm.

Mathematics
1 answer:
irinina [24]3 years ago
8 0

Answer:

192 cm^3

Step-by-step explanation:

Volume equals Area of the base times the height divided by three.

V = <u>length * width * height</u>

                      3

V = <u>8 * 6 * 12</u>   =   192 cm^3

           3

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What is the following product? 3 square root of d times 3 square root of d times 3 square root of d
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Answer:27d

Step-by-step explanation:

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3 years ago
If y is inversely proportional to the square root of x and y=−70 when x=49, find y if x=2401.
Dahasolnce [82]

The value of y when x= 2401 is -10

<h3>How to determine the value of x?</h3>

An inverse variation is represented as:

y = \frac{k}{\sqrt x}

Where k is the proportionality constant

When y = -70, x = 49

So, we have:

-70 = \frac{k}{\sqrt {49}}

Take the square root of 49

-70 = \frac{k}{7}

Multiply through by 7

k = -490

Substitute k = -490 in y = \frac{k}{\sqrt x}

y = -\frac{490}{\sqrt x}

When x =2401, we have

y = -\frac{490}{\sqrt {2401}}

Evaluate the square root

y = -\frac{490}{49}

Divide

y = -10

Hence, the value of y when x= 2401 is -10

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brainly.com/question/14254277

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4 0
2 years ago
Round to the nearest cent 2.303?
aksik [14]
2.3

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3 years ago
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3 years ago
The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.
Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

<em>Let X = number of hours spent per week on household chores</em>

So, assuming data follows normal distribution; X ~ N(\mu=28,\sigma^{2}=7^{2})

The z score probability distribution for sample mean is given by;

               Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean hours = 28

            \sigma = standard deviation = 7 hours

            n = sample of adults = 49

<em>Let </em>\bar X<em> = sample mean hours spent per week on household chores</em>

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P(\bar X > 26.75 hours)

    P(\bar X > 26.75 hours) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{26.75-28}{\frac{7}{\sqrt{49} } } ) = P(Z > -1.25) = P(Z < 1.25)

                                                                     = 0.89435  {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

4 0
3 years ago
Read 2 more answers
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