Answer:
The unit price of brant A and brand B is 0.1311 and 0.1704 and brand A would be better
Step-by-step explanation:
The computation of the unit price for each brand is shown below:
For brand A, the unit price is
= 2.36 ÷ 18 pencils
= 0.1311
For Brand b, the unit price is
= 4.09 ÷ 24
= 0.1704
So here as we can see that brand A would be better as it has less cost as compared with brand B
The answere is 213 boxes
If you add 3 dozens to 14 dozens of boxes of envilopes , then you get 17 dozens of boxes of envilopes.Then of you sum up the 1/2 (2/4 ) with the 1/4.You get 3/4. Finally, you add 17 dozens to 3/4 of a dozen you get 17 3/4 dozens( wich is 213 boxes )
Step-by-step explanation:
Hey there!
Given;
Radius of a circle (r) = 7cm
Now;
We know that;
Area of circle (a) = π*(r^2)
= 3.14*(7^2)
= 3.14*49
= 153.86 cm^2
Therefore, the area of a circle is 153.86 cm^2.
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
ANSWER
y varies inversely as x exponent 4.
EXPLANATION
The inverse variation equation is given as:

We can see that there is an inverse relation between the quantity y and x.
If the it were
, we say y varies inversely as the square of x.
Hence for the given relation,the precise definition is that, y varies inversely as x exponent 4.
Answer:
P(X ≥ 1) = 0.50
Step-by-step explanation:
Given that:
The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.
Then; the probability of success = 7/34 = 0.20588
Using Binomial distribution to determine the probability; we have:

where;
x = 0,1,2,...n and 0 < β < 1
and x represents the number of successes.
However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:
P(X ≥ 1) = 1 - P(X< 1)
P(X ≥ 1) = 1 - P(X =0)
![P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%20%7B%5E3C__0%7D%20%280.21%29%5E0%20%281-0.21%29%5E%7B3-0%7D%20%5Cbigg%5D)
![P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%201%20%5Ctimes%201%20%280.79%29%5E%7B3%7D%20%5Cbigg%5D)
P(X ≥ 1) = 1 - 0.50
P(X ≥ 1) = 0.50