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2 years ago

Hi can someone help me pls

Mathematics

2 answers:

vitfil [10]2 years ago

7 0

I think it’s 7ab squared

Black_prince [1.1K]2 years ago

4 0

Answer:

7a^2 b

Step-by-step explanation:

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Elaine bought 3 4/5 pounds of apples for $1.99 per pound, 3/4 pound of pears for $2.25 per pound, and 3 2/3 pounds bananas for $

stiv31 [10]

Answer:

1.$6.41

2.$1.68

3.$7.56

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the solution to the system of equations? Use the substitution method.

aleksandrvk [35]

{ y = 3 x - 4
9x -3y = 14

Subsititute y = 3x-4 :

[ 9 x - 3 ( 3 x-14 )=14]

Refine:

9 x - 3 ( 3 x - 4 ) = 14

- 2 = 0

is false , therefore the system of equations has no solution

Answer A

hope this helps!

3 0

3 years ago

Ari and Greg share a 12-ounce bucket of clay. By the end of the week, Ari has used 1 6 of the bucket, and Greg has used 2 3 of t

kotegsom [21]

Answer:

2 ounces of clay is left in the bucket

Step-by-step explanation:

Total amount of clay in the bucket = 12 ounce

Ari used 1/6th of the clay in the bucket and Greg used 2/3 of the clay in the bucket

Hence, the remaining clay in the bucket

12 - 1/6 *12 - 2/3 * 12

12 - 2-8

3 0

2 years ago

Rewrite in a form that does not use exponents

emmainna [20.7K]

Answer:

$\boxed{18}$

Step-by-step explanation:

One of the rules of logarithms is ...

log(a^b) = b·log(a)

So ...

$6\log_5{x^3}=6(3\log_5{x})=\bf{18}\log_5{x}$

4 0

3 years ago

A radar gun was used to record the speed of a swimmer (in meters per second) during selected times in the first 2 seconds of a r

Natalka [10]

Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
0.8+2.24+1.75+0.7=5.49

5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters

8 0

2 years ago