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Csc0sin20-sec0=cos20sec0
1 answer:
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Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:
Introducing the constant of proportionality
If 150 pounds is required for a distance of 10 inches from the object
- p=150 pounds
- d=10 inches
Therefore, the relationship between p and d is:
When d=3 Inches
The pressure applied when the distance is 3 inches is 500 pounds.