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3 years ago

Brianna's parents built a swimming pool in the backyard. Brianna says that the distance around the pool is 120 feet.

1 answer:

4 0

No, Brianna is not correct.
The distance around the pool is 131.4 ft

Step by step explanation:

1) Semi circle with a diameter equal to the side opposite it, 20 ft.
Find the length of half the circle:
Circumference of semi-circle = (1/2)(πd)
Where:
π = 3.14
d = 20 ft.
Circumference of semi-circle = (1/2)(3.14)(20 ft) = 31.4 ft.
2) Vertical lengths from the endpoint of semi-circle to the endpoints of horizontal lengths, 40 ft each ⇒ 2 × 40 ft. = 80 ft.
3.) Horizontal length at 20 ft.
Add the semi-circle, vertical, and horizontal lengths:
Distance around the pool = 31.4 ft + 80 ft. + 20 ft.
Distance around the pool = 131.4 ft.

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A rental car agency rents cars for $32 per day. They also charge $0.15 per mile driven. If you are taking a 5-day trip and have

xz_007 [3.2K]

So the equation is 32x+0.15y = $250
You know that you’re going to a 5-day trip so you can change x to 5
32(5)+0.15y = $250
You multiply 32 by 5 = 160
$160+0.15y = $250
And to simplify the equation(to make it easier) you subtract 160 on both sides
0.15y = $90
Now you’re trying to find y, so divide 90 by 0.15 to find the maximum of miles you can drive.
y = 600 mi
The maximum amount of miles you can drive is 600

Graph:
I can’t show any pictures sorry
But this is how you do it
Make a number line
Graph 600 with a closed circle, like this: ●
Then make an line going to the left(because you can’t go any more than 600)

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4 years ago

Find the missing angle. Find X

olga55 [171]

Answer:

I don’t know 160.

Step-by-step explanation:

20 plus 160 equals 180.

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3 years ago

Real World Scenario:

iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

Distance Train A is from the city: 750 - 75·t

Distance Train B is from the city: 50·t

After six hours, the two trains are the same distance from the city

At that time both trains will be 300 miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

Distance of Train A from the city is; x₁ = 750 - 75·t

Distance of Train B from the city is x₂ = 50·t

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

$t = \mathbf{\dfrac{750}{125}} = 6$

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

After 6 hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

At that time both trains will be 300 miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; 0 hours ≤ t < 6 hours

2) The Train B is further from the city after 6 hours of its departure from the city; t > 6 hours

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

The distance between the trains after 4 hours = 450 miles - 200 miles = 250 miles

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