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GenaCL600 [577]

3 years ago

13

|-25.6|+|-11.4| What is the answer to this

1 answer:

12345 [234]3 years ago

3 0

37. The absolute value symbol turns any negative number positive if it's within those brackets, so that's why the answer is positive. Hope this helped!

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Customers of a phone company can choose between two servers plans for a long-distance calls. The first plant has $27 monthly fee

Marina86 [1]

First, you set up your equation then you put the pieces together to get the answer

7 0

3 years ago

Use integration by parts to find the integrals in Exercise.<br> ∫^3_0 3-x/3e^x dx.

Viefleur [7K]

Answer:

8.733046.

Step-by-step explanation:

We have been given a definite integral $\int _0^3\:3-\frac{x}{3e^x}dx$ . We are asked to find the value of the given integral using integration by parts.

Using sum rule of integrals, we will get:

$\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx$

We will use Integration by parts formula to solve our given problem.

$\int\ vdv=uv-\int\ vdu$

Let $u=x$ and $v'=\frac{1}{e^x}$ .

Now, we need to find du and v using these values as shown below:

$\frac{du}{dx}=\frac{d}{dx}(x)$

$\frac{du}{dx}=1$

$du=1dx$

$du=dx$

$v'=\frac{1}{e^x}$

$v=-\frac{1}{e^x}$

Substituting our given values in integration by parts formula, we will get:

$\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(x*(-\frac{1}{e^x})-\int _0^3(-\frac{1}{e^x})dx)$

$\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))$

$\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx=3x-\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))$

Compute the boundaries:

$3(3)-\frac{1}{3}(-\frac{3}{e^3}- (\frac{1}{e^3}))=9+\frac{4}{3e^3}=9.06638$

$3(0)-\frac{1}{3}(-\frac{0}{e^0}- (\frac{1}{e^0}))=0-(-\frac{1}{3})=\frac{1}{3}$

$9.06638-\frac{1}{3}=8.733046$

Therefore, the value of the given integral would be 8.733046.

6 0

3 years ago

A concrete stepping stone measures 20 square inches. What is the area of 30 such stones

Natalka [10]

The answer is 600. 30•20

7 0

3 years ago

14. The area of 10 square plots is 160 ares. Find the length in metres of the side of each plot (3mks)

VashaNatasha [74]

Answer:

Step-by-step explanation:

1 are = 100 m²

Assuming the ten squares are congruent, the area of each square is 160/10 = 16 are

16 are × 100 m²/are = 1600 m²

each side is √1600 = 40 m

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B36%7D%7B169%7D%7D" id="TexFormula1" title="\sqrt{\frac{36}{169}}" alt="\sq

otez555 [7]

Answer:

0.0355029585799?

Step-by-step explanation:

5 0

3 years ago