Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that :
Number of teams = 14
Each team plays every other team twice ;
Using the combination formula :
nCr = n! ÷ (n-r)! r!
14C2 = 14! ÷ (14 - 2)! 2!
14C2 = 14! ÷ (12)! 2!
14C2 = (14 * 13) ÷ 2 * 1
14C2 = 182 / 2
14C2 = 91
Hence, since they are going to be playing each other twice :
2(14C2)
2 * 91 = 182games
Answer:
Step-by-step explanation:
You could use the 'brute force' method, which would be to simply write out all the possible subsets. We could avoid repetition within the subsets.
{2} would be the first subset; it contains one even number.
Next would be {2, 4}, next {2, 4, 6} ... {2, 4, 6, ... 94, 96, 98, 100}. Provided that we correctly understand what this problem is asking for, writing out and then counting all these subsets should answer the question.
Two angles are complementary angles if they have a sum of 90 degrees. We could write the expression as below.
angle 1 + angle 2 = 90
7x + 2 + 3x - 2 = 90
solve for x by adding like terms
7x + 3x + 2 - 2 = 90
10x = 90
x = 90/10
x = 9
The value of x is 9