Find the sum of the first 6 terms of the following series, to the nearest integer.
1 answer:
Answer:
1008
Step-by-step explanation:
geometric sequence:
a=16
r=32/16=2
Sum of GS:
s=a(1-r^n)/(1-r)
S(6)=16(1-2^6)/(1-2)
=1008
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