a= 34 degrees
b= 28 degrees
c= 62 degrees
Step-by-step explanation:
First you know that b is 1/2 of 56 degrees or 28.
The triangle with the a in it is isoceles because the two sides are both radii.
In the triangle the top angle = 112 because it is a centeral angle to the 112 arc.
Angle a and opposite to a are equal and then have to be 34 degrees to equal 180.
We know two arc lengths are 112 and 56 and the one with angle a has to be 34x2 or 68.
a whole circle equals 360.
360-56-68-112 = 124
Angle c = 1/2 of 124, or 62 degrees
Answer
She used 6/15 litres of oil in January
Explanation
We are given that, in January, she used 3/5 of the amount of oil she used in February.
We are also given that, she used 2/3 litres of oil in February.
Therefore, amount of oil used in January is:
3/5 • 2/3 = 6/15
She used 6/15 litres of oil in January
Answer:
5.625 inches
Step-by-step explanation:
Given that:
Total Rainfall in inches (P) = 8 inches
The runoff volume (in inches) Q = ???
The curve number CN = 80
Recall that: The runoff volume can be calculated by using the formula:
for P > 0.2S
Q = 0 for P < 0.2S
where:
curve number CN = 80
S = 2.5 inches
Since the rainfall (P) is greater than 0.25
Then:
Q = 5.625 inches
Thus, the runoff volume = 5.625 inches
-4x-8+6=5-3x-3 distribute
-4x-2=2-3x combine like terms
-4=x combine like terms with addition and subtraction
x=-4 final answer
Answer:
The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°
Step-by-step explanation:
From the above question,
We have:
Camera 1 = Angle A
Camera 2= Angle B
Camera 3 = Angle C
A = 210ft
B = 234ft
C = 260ft
We need to find Angle A( angle of camera 1) using the cosine rule
A=(B² + C² - 2BCCosA)
210² = 234² + 260² - 2 × 234 × 260 × CosA
210² = 122356 - 121680CosA
Square both sides
210² = 122356 - 121680CosA
44100 = 122356 - 121680CosA
121680CosA = 122356 - 44100
121680CosA = 78256
Cos A = 78256/121680
Cos A = 0.6431295201
A = arc cos (0.6431295201)
A = 49.974422249°
Angle A approximately = 49.97°
Using the Sine rule to find the Angle B
A/Sine A = B/Sine B
210ft/Sine 49.97° = 234ft/Sine B
210ft × Sine B = 49.97° × 234ft
Sine B =( Sine 49.97° × 234ft)/210ft
B = arc sin (0.8532172354)
Angle B = 58.56334
Approximately = 58.56°
Angle C = 180 - (49.97 + 58.56)°
Angle C = 71.47°
Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°
