Answer:
sin^2 A
Step-by-step explanation:
first expand the trigonometry
1(1-cosA)+cosA(1-cosA)
=1-cosA+cosA-cos^2 A
= 1-cos^2 A
from trigonometric identity sin^2 A + cos^2 A= 1
sin^2 A= 1- cos^2 A
=sin^2 A
The value of x is 1.14 or x = -1.47
We find the value of x in the quadratic equation 3x^2 +x-5=0
Using the formula: (-b ± √ (b²- 4 a c)) / (2a)
Where the value of a = 3, b = 1 and c = -5
Substituting the above values (a = 3, b = 1 and c = -5)
in the formula:
(-1 ± √ (1²- 4 3 (-5))) / (2*3)
= (-1 ± √ (1+60)) / (6)
= (-1 ± √ (61)) / (6)
= (-1 ± 7.81) / (6)
= (-1 + 7.81) / (6) or (-1 -7.81) / (6)
= (6.81) / (6) or (-8.81) / (6)
=1.135 or -1.468
Hence the value of x= 1.14 or -1.47
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Answer: 11.4
Step-by-step explanation:
I did part / whole = % / 100
So x / 76 = 15 / 100
76 x 15 = 1140
1140 ÷ 100 = 11.4
14. 6.4 blocks
15. 1.78
16. 7.47
Answer:
Explanation:
Identity: sec2θ=1+tan2θ
sec2(π2−x)−1=1+tan2(π2−x)−1
=tan2(π2−x)
Identity: tan(π2−θ)=cotθ
=cot2x