Let's the name the first number x and the consecutive number x + 1. The sum of both of these numbers equals to 53.
We now have our equation:
x + x + 1 = 53
Now solve for x.
x + x + 1 = 53
2x + 1 = 53 <-- Combine like terms
2x = 52 <-- Subtract 1 from each side
x = 26
So, the first number is 26 and the second number is 27.
Answer:
Step-by-step explanation:
First off, since we're talking about finding the correct hypotenuse for the triangle, we know to use the Pythagorean Theorem:
a^2+b^2=c^2
Since we know from the question, 32 and 22 are not the hypotenuse we know that those two values would be a and b. Now, all we do is stick these both into the equation and solve!





Answer:
42
Step-by-step explanation:
The correct choice is marked.
If you follow instructions, you will compute the quotient for each value in the set:
2520 ÷ 30 = 84
2520 ÷ 42 = 60 . . . . . the value we're looking for (we need go no further)
2520 ÷ 84 = 30
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The easier way to solve the problem is to multiply the equation by x/60, so you have ...
2520 ÷ 60 = x
Then, you're doing one division instead of two or three.
2520 ÷ 60 = 42 = x