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Kazeer [188]
3 years ago
8

Jon is working on a city councilperson’s election campaign. He wants to survey potential voters about their opinions. Which is t

he best way for him to gather a sample?
A. Attend a speech given by the councilman and survey audience member.
B. Select every 10th person on a list of registered voters and call them to complete the survey.
C. Go to the gym during the day and survey people as they exercise.
D. Hand out flyers at the supermarket asking people to call and complete a survey.
Mathematics
2 answers:
const2013 [10]3 years ago
6 0
I would go with the answer b 
Naya [18.7K]3 years ago
6 0
The answer would be A because He needs to no what every one thinks
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3 years ago
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
A farmer estimated that there were 25 gallons of water left in a tank. If this is an underestimate by 16%, how much water was ac
djyliett [7]

Answer:

The actual water in the tank is 29.76 gallons.

Step-by-step explanation:

It is given that the farmer estimated amount of water is 25 gallons.

It is also given that he underestimate the water in tank by 16%.

Let the actual water in tank be x.

(1-\frac{16}{100})x=25

(\frac{100-16}{100})x=25

84x=25\times 100

x=\frac{2500}{84}

x=29.7619

x\approx 29.76

Therefore the actual water in the tank is 29.76 gallons.

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3 years ago
Solve the inequality 3x - 5 &lt; 4.
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Answer:

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Step-by-step explanation:

Since 3x - 5 < 4 then we can transpose the inequality to make x the subject of the equation:

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⇒       x < 9 ÷ 3

⇒       x < 3

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Give the rest of the question
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