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Viktor [21]
3 years ago
6

2v^6+28v^3+98 what’s the answer this this ?

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0
If you are trying to factor this problem then the answer is 
2(v^3+7)^2

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Given: ∠AOC, ∠BOC - complementary angles
34kurt

Answer:

  • 30
  • COB . . . . or . . . . BOC

Step-by-step explanation:

The reason given on the line of interest is "substitution," so the problem boils down to determining what was substituted for what. The previous statement says ...

  AOC + COB = 90

and the first part of the statement we're to complete has BOC + ___.

We see from the given statements that m∠AOC = m∠BOC + 30°, so it appears that is the substitution that has been made: AOC has been replaced by BOC + 30.

This means the first blank is filled with 30.

__

The second part of the previous statement is ...

  AOC + COB = 90

so we believe this (COB) should go in the second blank.

__

Then the line of interest would read ...

  BOC + 30 + COB = 90

_____

<em>Comment on the problem</em>

There is a curious mix of notations here. Usually, (as in the beginning of this problem) we refer to the measure of an angle using "m∠" in front of the angle designator, and we use a degree symbol to indicate the units of that measure. Part-way through the problem statement written here, those notations were dropped, and we're to assume they are intended. IMO, this is a poor way to demonstrate careful problem solving.

The substitution given for AOC is BOC+30, but the line into which that is substituted has AOC +COB = 90. This means the equation after substitution is ...

  BOC +30 +COB = 90

Since BOC and COB are the same angle, we can sort of fudge the "algebra" to get to  BOC=30, but if the problem were more carefully written, the angle would be referred to by consistent nomenclature:

  m∠AOC + m∠BOC = 90° . . . . . . . . . preferred angle designations

  (m∠BOC + 30°) + m∠BOC = 90° . . . . substitution for m∠AOC

  2(m∠BOC) = 60° . . . . . . algebra (subtract 30°, collect terms)

  m∠BOC = 30° . . . . . . . . algebra (divide by 2)

3 0
3 years ago
The formula c = √a^2 + b^2 represents the length of the hypotenuse of a right triangle with side lengths a and b. Solve the equa
Eduardwww [97]

Answer:

b = √(c^2 - a²)

Step-by-step explanation:

Start with the given c = √a^2 + b^2.  Squaring both sides, we get:

c² = a² + b².

We want to iosolate b² and then b.

So:  subtract a² from both sides, resulting in:

c² - a² = b²

Taking the square root of both sides, we get:

√b² = √(c² - a²)

and so:

b = √(c^2 - a²)

7 0
3 years ago
Quadrilateral ABCD is dilated by a scale factor of 3/2 to create quadrilateral A'B'C'D'. If quadrilateral ABCD has an area of 30
kow [346]

Answer:

67.5

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.

Dilation is the enlargement or reduction of an object by a factor.

The area of ABCD = AB * BC = 30

As a result of the dilation to form A'B'C'D', A'B' = 3/2 * AB, B'C' = 3/2 * BC, C'D' = 3/2 * CD and A'D' = 3/2 * AD. Hence:

Area of A'B'C'D' = A'B' * B'C' =  3/2 * AB * 3/2 * BC = 9/4 * (AB * BC) = 9/4 * 30 = 67.5

5 0
3 years ago
p: If two out of five people use the subway every day, then the probability of a person using the subway is 0.4.
Alexandra [31]

2 divided by 5 = 0.4

 so that statement is true.

3 0
3 years ago
Read 2 more answers
Solve the equation below for a<br><br> vf=vi+at
ipn [44]

Answer:

a=\frac{vf - vi }{t}

Step-by-step explanation:

vf=vi + at

vf-vi= at

divide  both sides by t

\frac{vf - vi }{t} =\frac{at}{t}

a=\frac{vf - vi }{t}

6 0
3 years ago
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