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PilotLPTM [1.2K]
2 years ago
6

Which decimal is equivalent to forty and seventy six thousands ? a.40.076 b 40.76 C 47.006 D 47.06​

Mathematics
1 answer:
krek1111 [17]2 years ago
7 0

Answer:

A. 40.076

Step-by-step explanation:

Because B is forty and seventy six hundredths. C is forty-seven and six thousandths. D is forty-seven and six hundredths.

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The following lines are ______ <br><br> 4x + 2y = 10 y = -2x + 15
zmey [24]

Answer:

Parallel

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

4x + 2y = 10 ( subtract 4x from both sides )

2y = - 4x + 10 ( divide through by 2 )

y = - 2x + 5 ← in slope- intercept form

with slope m = - 2

and

y = - 2x + 15 ← is in slope- intercept form

with slope m = - 2

• parallel lines have equal slopes

then the 2 lines are parallel

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1 year ago
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There are seven balls in a bag(red, orange, green, yellow, white, black, and purple. If you draw a ball and flip a coin, the cha
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The chance of purple is 14% and the chance of tails is 50%. 
 
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3 years ago
The symmetry of a hyperbola with a center at (h, k) only occurs at y = k.<br> True<br> False
Lyrx [107]
False
Its other axis of symmetry is at x = h.
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A coin is tossed 5 times find the probability that none are head
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20%

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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