Answer:
It’s 60miles
Step-by-step explanation:
We assume the trip is "d" miles and that the "extra hour" refers to the additional time that a current of 2 mph would add. That is, we assume the reference time is for a current of 0 mph.
The time with no current is ...
time1 = distance/speed
time1 = d/12 . . . . hours
With a current of 2 mph in the opposite direction, the time is ...
time2 = d/(12 -2) = d/10
The second time is 1 hour longer than the first, so we have ...
time2 = 1 + time1
d/10 = 1 + d/12
6d = 60 + 5d . . . . multiply by 60
d = 60 . . . . . . . . . subtract 5d
The one-way distance is 60 miles.
Answer:
Please check the explanation.
Step-by-step explanation:
Given the function
We know that the domain of the function is the set of input or arguments for which the function is real and defined.
In other words,
- Domain refers to all the possible sets of input values on the x-axis.
Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.
as x³ - 16x ≥ 0
Thus, identifying the intervals:
Thus,
The domain of the function f(x) is:
![x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}](https://tex.z-dn.net/?f=x%5Cleft%28x%2B4%5Cright%29%5Cleft%28x-4%5Cright%29%5Cge%20%5C%3A0%5Cquad%20%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3A-4%5Cle%20%5C%3Ax%5Cle%20%5C%3A0%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%5Cge%20%5C%3A4%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%5Cleft%5B-4%2C%5C%3A0%5Cright%5D%5Ccup%20%5C%3A%5B4%2C%5C%3A%5Cinfty%20%5C%3A%29%5Cend%7Bbmatrix%7D)
And the Least Value of the domain is -4.
Answer: no solution
Step-by-step explanation:
They have the same slope which means they are parallel lines that will never cross or intersect. This mean that there is no solution
Answer:
3000 feets
Step-by-step explanation:
Given that :
Initial Ascent to steady altitude = 35,000 feets
Descent to steady altitude = 32,000 feets
Number of feets the plane descend :
(Initial ascent to steady altitude - descent to steady altitude)
(35000 - 32000) feets = 3,000 feets
