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Lyrx [107]
3 years ago
12

Find the volume of a 1 km3 body of water in m3, and select the correct units.

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

1,000,000,000 m^3

Step-by-step explanation:

1 kilometer is equal to 1000 meters, and 1 km^3 is 1 km * 1 km * 1 km

Therefore,

1000m * 1000m * 1000m = 1,000,000,000 m^3

Hope this answer helped! :)

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Rainbow [258]
Option A

x+8=-3
x+8-8=-3-8
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7 0
3 years ago
A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32 centimeters, and the le
nataly862011 [7]

Answer:

Step-by-step explanation:

You need the Pythagorean Theorem to solve this question. There is no be part.

Equation

c^2 = a^2 + b^2

Givens

a = 32

b = 21

c = ?

Solution

c^2 = a^2 + b^2              Substitute the values

c^2 = 32^2 + 21^2          Expand

c^2 = 1024 + 441            Combine

c^2 = 1465                     Take the square root of both sides

√c^2 = √1465  

c = 38.275

Answer: 38.3 rounded

6 0
2 years ago
Can someone awsner this for me honestly I’m sorry but I really need these awsner but I need the answers for these 3 to
zalisa [80]

1. 50 + 20x = 240

2. 85% so more than 75%

3. 25.9% so about 26%

Hope this helps and please consider marking branliest if this helped you

5 0
3 years ago
Read 2 more answers
-1.2 = 1.8x<br> what does x equal?
Eddi Din [679]

Answer:

Step-by-step explanation:

. 6

6 0
3 years ago
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4.8.4 Raw materials are studied for contamination. Suppose that the number of particles of contamination per pound of material i
forsale [732]

Answer:

700 lbs and 3.742

Step-by-step explanation:

Given that raw materials are studied for contamination. Suppose that the number of particles of contamination per pound of material is a Poisson random variable with a mean of 0.02 particle per pound.

a) To get 14 particles of contamination we must have

expected number of pounds = \frac{14}{0.02} \\=700

b) Since for 700 pounds particles expected are 14 we can say in  a Poisson distribution mean and variance are equal

i.e. Var (700 lbs to obtain 14 particles of contamination ) = 14

Std deviation =\sqrt{14} =3.742

5 0
3 years ago
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