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Naya [18.7K]
3 years ago
9

A communication pattern in which the parties slowly reduce their dependence on one another, withdraw, and become less invested i

n the relationship is called _______________. A. an avoidance spiral B. a disconfirming response C. an escalatory conflict spiral D. evaluative communication
Computers and Technology
1 answer:
zepelin [54]3 years ago
7 0

Answer:

The correct answer to the following question is option A. an avoidance spiral.

Explanation:

An avoidance spiral is a spiral in which parties avoid the conflicts at all cost in which leads to reducing the influence, dependence, etc. This spiral can also be destructive.

In other words, it is the only spiral in parties slowly reduces their dependence and the influence on the one and another.

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4. Select the correct answer.
3241004551 [841]

Answer: B.  PDF

Explanation:

Portable Document Format (PDF) is such an important document that it is considered the international standard for information and document exchange. It is used for letters, resumes and even electronic contracts.

PDF was developed by Adobe to make it independent of the device or application it is being viewed on and combines layers of information into one layer thereby making it a flat document.

7 0
3 years ago
Write a recursive method named binarySearch that accepts a sorted array of integers and an integer target value and uses a recur
djyliett [7]

Answer:

10

-1

Process finished with exit code 0

Explanation: see code bellow

public class BinarySearchRecursive {

   public static int binarySearch(int[] a, int key) {

       return binarySearchRecursiveHelper(a, key, 0, a.length - 1);

   }

   public static int binarySearchRecursiveHelper(int[] arr, int target, int start, int end) {

       if (start > end) {

           return -1;

       }

       int mid = (start + end) / 2;

       if (arr[mid] == target) {

           return mid;

       } else if (target < arr[mid]) {

           return binarySearchRecursiveHelper(arr, target, start, mid - 1);

       } else {

           return binarySearchRecursiveHelper(arr, target, mid + 1, end);

       }

   }

   public static void main(String[] args) {

       int[] a = {-4, 2, 7, 10, 15, 20, 22, 25, 30, 36, 42, 50, 56, 68, 85, 92, 103};

       int index = binarySearch(a, 42);   // 10

       System.out.println(index);

       index = binarySearch(a, 66);   // -1

       System.out.println(index);

   }

}

6 0
3 years ago
The approved detail design resulting from the __________ serves as a basis for making the decision to begin production.
natita [175]
I am pretty sure, that complete answer looks like this: The approved detail design resulting from the <span>Critical Design Review</span> serves as a basis for making the decision to begin production. Critical Design Review is needed to ensure that system can meet stated performance including costs and risks.
8 0
3 years ago
Discribe two ways you can zoom in and out from an image
krek1111 [17]

Answer:

Select the Zoom tool, and then do any of the following:

<h2>#1. </h2>

Click and hold in the image to zoom in. Press Alt (Windows) or Option (Mac OS) to zoom out.

<h2>#2!</h2>

In the options bar, select Scrubby Zoom. Then drag to the left in the image to zoom out, or to the right to zoom in.

<h2>psst! pls, brailiest!</h2>
3 0
3 years ago
Read 2 more answers
) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in
erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0
3 years ago
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