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mote1985 [20]
2 years ago
11

describe the process of transformation from start to finish. Be sure to use the following terms in your response: restriction en

zyme, ligase, plasmid, DNA, protein, gene, and sticky ends, and recombinant DNA.
Biology
1 answer:
Lunna [17]2 years ago
5 0

Answer:

Explanation:

Did you get the answer

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Ling made a study chart for science class.
aliina [53]

Alyssa's additional observation would be cell Y having a larger vacuole than cell X. The third option is the correct one.

<h3>Plant cell vs animal cell</h3>

From the observations, both cells are eukaryotic. This is because:

  • cell X has lysosomes which are only found in eukaryotic cells
  • cell Y has a nucleus which also peculiar to eukaryotic cells only

Lysosome houses digestive enzymes and is found mostly in animal cells. Only a few plant cells have lysosomes.

Thus, the lack of a lysosome means that cell Y is a plant cell while the presence means that cell X is an animal cell.

Generally, plant cells have larger vacuoles than animal cells.

More on plant and animal cells can be found here: brainly.com/question/1493437

#SPJ1  

4 0
2 years ago
What will happen to your body if you go without eating protein?
Tpy6a [65]
B because it’s resonable
7 0
3 years ago
A certain buffer is made by mixing a weak acid HA and its conjugate base A–. When HA is present at a concentration of 0.5 mM and
MAVERICK [17]

Answer:The ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

Explanation:

The dissociation constant for formic acid = K_a=1.8\times 10^{-4}

Concentration of HA= 0.5 mM

Concentration of A^-= 0.1 mM

pH = 6.16

First we have to calculate the value of K_a.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[A^-}{[HA]}

Now put all the given values in this expression, we get:

6.16=pK_a+\log (\frac{[0.1]}{0.5})

pK_a=6.86

To calculate the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02.

Using Henderson Hesselbach equation :

7.02=6.86+\log \frac{[A^-]}{[HA]}

7.02=6.86+\log \frac{[A^-]}{[HA]}

\frac{[A^-]}{[HA]}=1.44

\frac{[HA]}{[A^-]}=0.69

Thus the ratio of the concentrations of HA  and A^- when the buffer has a pH of 7.02 is 0.69

7 0
3 years ago
People who have 5 fingers on each hand are
barxatty [35]

Answer:

humans

Explanation:

because I'm smart and I am a human

8 0
3 years ago
Read 2 more answers
If a sample of DNA contains 25% adenine, what percent Thiamine would it contain
Anna35 [415]

Answer:

25%

Explanation:

adenine and thymine are base pairs so there will be an equal amount of adenine to thymine.

4 0
3 years ago
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