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kirill115 [55]
3 years ago
9

Find the probability of the following events , when a dice is thrown once:

Mathematics
2 answers:
Fudgin [204]3 years ago
7 0

Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

Favourable cases for a prime number are 2,3,5,

i.e., n(A)=3

Hence P(A)=n(A)n(S)=36=12

(b) Let A be an event ''getting a number between 3 and 6''.

Favourable cases for events A are 4 or 5.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(c) Let A be an event ''a number greater than 4''.

Favourable cases of events A are 5, 6.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(d) Let A be the event of getting a number at most 4.

∴ A={1,2,3} ⇒ n(A)=4,n(S)=6

∴ Required probability =n(A)n(S)=42=23

(e) Let A be the event of getting a factor of 6.

∴ A={1,2,36} ⇒ n(A)=4,n(A)=6

∴ Required probability =46=23

(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

i.e., n(A)=5

Hence P(A)=n(A)n(S)=536

(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

P(A)=n(A)n(S)=636=16

(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

i.e., n(A)=4

P(A)=n(A)n(S)=436=19

(iii) We have, n(S) = 36

(a) Let A be an event ''a sum less than 7'' i.e., 2,3,4,5,6.

Favourable cases for a sum less than 7 ar

hammer [34]3 years ago
3 0
The correct answer is number 7
Hope this help?
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Answer:

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Step-by-step explanation:

w+w+l+l= perimeter

if the length is 3m less than twice the width then let's do some math.

42 divided 2 =21. so the width and length of one side have to equal 21. For example, let's use 8 as the width. The length would be twice(16) minus three(13) 13 plus 8 is 21. WOW it equals half of it so no we know the length is 13 and the wdith is 8.

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Danielle’s aunt is 8 years than 3 times Danielle’s age. Her aunt is 34. Write an equation that relates Danielle’s age, a, to her
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Answer:

*Assuming that the question should read '8 years less than 3 times Danielle's age'*

Equation:  3a - 8 = 34, where 'a' = Danielle's age

Danielle's age (a) = 14

Step-by-step explanation:

Using key words and phrases from the problem, we can find Danielle's age by setting up an equation to solve for 'a'.  

Since Danielle's aunt is '8 years less than 3 times Danielle's age' her aunt's age can be written as:  3a - 8.  We also know her aunt is 34.  So, the equation becomes:

3a - 8 = 34

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Kristin spent $120 on shirts. Dress shirts cost $40 and t-shirts cost $8. If she bought a total of 7 shirts, then how many of ea
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Answer:

The correct answer is: She bought 2 dress shirts and 5 t-shirts

Step-by-step explanation:

Let's marked dress shirts with x and t-shirts with y.

Now we will make equations to solve this problem:

x + y = 7  =>  y = 7 - x

40 x + 8 y = 120

When we replace y = (7 - x) in the previous equation we get:

40 x + 8 (7 -x) = 120  40 x + 56 - 8 x = 120  => 32 x = 120 - 56 =>

32 x = 64  => x = 64/32 = 2 => x = 2

y = 7 - x = 7 - 2 = 5 =>  y = 5

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