Is this function linear or nonlinear? *

Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)

dsp73

Answer:

a) $\log 52$

b) $\log_57$

Step-by-step explanation:

Use logarithm properties:

$\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}$

Then

a) $\log 13+\log 4=\log 13\cdot 4=\log 52$

b) $\log_514-\log _52=\log _5\dfrac{14}{2}=\log _57$

7 0

3 years ago

Find the value of x. PLS HELP ANSWER ASAP!

BARSIC [14]

Answer: x = 24º

Step-by-step explanation:

180 - 94 - 41 = 45

x + 111 + 45 = 180

x + 156 = 180

x = 24

7 0

2 years ago

Need help ASAP. The diagram shows 5ft student standing near a tree. The shadow of the student and the shadow of the tree at endp

Dmitry_Shevchenko [17]

Answer:

25 ft

Step-by-step explanation:

The 2 triangles are similar hence the ratios of corresponding sides are equal, that is

$\frac{x}{5}$ = $\frac{40}{8}$ = 5

multiply both sides by 5

x = 5 × 5 = 25

The height of the tree is 25 ft

3 0

2 years ago

(74pts) I offer all my points to anyone but help me! Write a real-world problem that can be represented by the algebraic equatio

musickatia [10]

<span>Jane is playing a game with Mike. Right now, Mike is winning, he has 10 more than 5 times the points that Jane has. If Jane has 47 points, how many points does Mike have?

or you could do

</span><span>Martha is doing an inventory of all the goods in her shop. For the brand Toms shoes, she should have recieved an order that would have brought the total number of Toms shoes in her store to 10 more than 5 times the number of shoes she has now. If Martha has 89 pairs of Toms in her store, how many would she have had, if she had recieved the delivery?

hope this helped :)
alisa202</span>

3 0

3 years ago

Read 2 more answers

The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t

Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.054.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.054\frac{54}{\sqrt{430}} = 5.35$

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

8 0

2 years ago