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svet-max [94.6K]
3 years ago
11

Seis albañiles hicieron una barda de 180 m2 durante 12 días. ¿Cuántos días necesitaran 5 albañiles para levantar una barda de 10

0 m2 ?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

8 dias

Step-by-step explanation:

Primero tenemos que averiguar cuantos m2 pueden levantar los seis albañiles en 1 dia. Esto lo calculamos dividiendo los 180m2 por los 12 dias que les llevo hacerlo.

180 / 12 = 15 m2 por dia

Ahora tenemos que dividir este numero por los 6 albañiles para calcular cuantos m2 hace 1 albañil por dia

15 / 6 = 2.5

Ahora tenemos que multiplicar este m2 por los 5 albañiles que pide la pregunta

5 * 2.5 = 12.5 m2 por dia

Finalmente, necesitamos dividir los 100 m2 por los 12.5 m2 que pueden hacer los 5 albañiles por dia.

100 / 12.5 = 8 dias

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saveliy_v [14]

Answer:4

Step-by-step explanation:

i think?

maybe 5

5 0
3 years ago
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0.6cm squared to mm squared
san4es73 [151]
1 cm = 10 mm

1 cm^2 = 100 mm^2

0.6 cm^2 = 0.6 * 100 mm^2 = 60 mm^2
3 0
4 years ago
Find The art length of a sector with an area of 8 square units.
frez [133]
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
A=8\\
r=4
\end{cases}\implies 8=\cfrac{\theta \pi 4^2}{360}\implies \cfrac{8\cdot 360}{4^2\pi }=\theta 
\\\\\\
\cfrac{2880}{16\pi }=\theta \implies \boxed{\cfrac{180}{\pi }=\theta }\\\\
-------------------------------\\\\

\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =\frac{180}{\pi }\\
r=4
\end{cases}\implies s=\cfrac{\frac{180}{\underline{\pi} }\underline{\pi} \cdot 4}{180}\implies s=\cfrac{\underline{180}\cdot 4}{\underline{180}}
\\\\\\
\boxed{s=4}

if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.
6 0
3 years ago
The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
3 years ago
I need a-n answers!!! help plseaseeeee
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A = consecutive interior
b= alternate exterior
c= consecutive exterior
d= alternate interior
e= corresponding
f= none
g= consecutive exterior
h= corresponding
i= alternate exterior
j= consecutive exterior
k=corresponding
l= alternate exterior
m= alternate interior
n= consecutive interior
5 0
4 years ago
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