Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
If segment AB is perpendicular to segment CD, then a right angle (90°) is formed.
7x + 27 = 90
7x = 63
x = 9
Answer:
x = 10°
Step-by-step explanation:
Step 1:
92° + x° + 78° = 180° Supplementary Angles
Step 2:
x° + 170° = 180° Combine Like Terms
Step 3:
x° = 180° - 170° Subtract 170° on both sides
Answer:
x = 10°
Hope This Helps :)
