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3 years ago

Can you guys help? (And explain or show your work if you can)

Mathematics

1 answer:

dedylja [7]3 years ago

7 0

Answer:

f(x)=4×-2,g(x)=2(x)+8

h(x)=f(x)+g(x)

solution:

h(x)=f(x)+g(x)

=4x-2+2x+8

4x+2x=8+2

6x=10

6x/6=10/6

x=5/3

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Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

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The sample size is n = 600

Generally the standard deviation is mathematically represented as

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$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

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=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

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Can you guys help? (And explain or show your work if you can)​

Can you guys help? (And explain or show your work if you can)