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2 years ago

Please help! Marking brainliest if correct.

Mathematics

2 answers:

mariarad [96]2 years ago

5 0

X=30 the work is below in case you need more help

Elena L [17]2 years ago

3 0

Answer:

x = 30

Step-by-step explanation:

A straight angle is 180 degrees, meaning the two angles given add up to 180.

5x + x = 180

6x = 180

x = 30

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Yuliya22 [10]

Answer:

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Step-by-step explanation:

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2 years ago

4x+(7-3)5=10 please help with this one

Ostrovityanka [42]

Answer:

x=-2.5

Step-by-step explanation:

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3 years ago

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Find the function value. tan495°

inysia [295]

Answer: -1

Step-by-step explanation:

You want to find an angle that is coterminal to 495. So, subtract 360 degrees until youre in the range of 0-360. I got 495 - 360 = 135°

Tangent is equal to $\frac{sin(theta)}{cos(theta)}$ , we already solved theta which was 135°

This next part is hard to explain to someone who doesnt know their trig circle, idk if you do. The angle 135 is apart of the pi/4 gang. So we know this is going to be some variant of √2/2. Sine of quadrant 1 and 2 is gonna be positive:

$sin135=\frac{\sqrt{2} }{2}$

Now lets do cosine of 135°, which again is apart of the pi/4 gang because its divisible by 45°. Its in quadrant 2 so the cosine will be negative.

$cos135=-\frac{\sqrt{2} }{2}$

The final step is to divide them. They are both fractions so you should multiply by the reciprocal.

$\frac{\sqrt{2} }{2} *-\frac{2}{\sqrt{2} } =-\frac{2\sqrt{2} }{2\sqrt{2} } =-1$

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3 years ago

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How do you solve this?

Katarina [22]

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] ~\dotfill\\\\ (x-6)^2+(y+5)^2=16\implies [x-\stackrel{h}{6}]^2+[y-(\stackrel{k}{-5})]^2=\stackrel{r}{4^2}~\hfill \begin{cases} \stackrel{center}{(6,-5)}\\ \stackrel{radius}{4} \end{cases}$

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3 years ago

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X = -2y + 300 3y = 800 - 4x

devlian [24]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x=-2y+300&(1)\\3y=800-4x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\3y=800-4(-2y+300)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3y=800+(-4)(-2y)+(-4)(300)\\\\3y=800+8y-1200\\\\3y=8y-400\qquad\text{subtract}\ 8y\ \text{from both sides}\\\\-5y=-400\qquad\text{divide both sides by (-5)}\\\\y=80\\\\\text{Put it to (1):}\\\\x=-2(80)+300\\\\x=-160+300\\\\x=140$

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2 years ago

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