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Bogdan [553]
3 years ago
11

Plz Solve Will Mark Brainliest and No Stealing Points Or Will Report Part 2

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

Before we graph y = -\frac{1}{2}x, we know that the slope, mx, could be read as \frac{rise}{run}. To graph the the equation of the line, we begin at the point (0,0). From that point, because our rise is negative (-1), instead of moving upwards or vertically, we will move downards. Therefore, from point 0, we will vertically move downwards one time. Now, our point is on point -1 on the y-axis. Now, we have 2 as our run. From point -1, we move to the right two times. We land on point (2,-1). Because we need various points to graph this equation, we must continue on. In the end, the graph will look like the first graph given.

For the equation y = 2, the line will be plainly horizontal. Why? Because x has no value in the equation. The variable x does not exist in this linear equation. Therefore, it will look like the second graph below. We graph this by plotting the point, (0,2), on the y-axis.

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sum=n+m=-2+5=3 is a answer

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What is the equation of the line that passes through (5, 3) and (4, 5)
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Answer:

y = - 2x + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (5, 3) and (x₂, y₂ ) = (4, 5)

m = \frac{5-3}{4-5} = \frac{2}{-1} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 5), then

5 = - 8 + c ⇒ c = 5 + 8 = 13

y = - 2x + 13 ← equation of line

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Verify the following trig identities​.
bagirrra123 [75]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• 1 + cot² x = csc²x and csc x = \frac{1}{sinx}

• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Consider the left side

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= sin²Θ × csc²Θ

= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified

-----------------------------------------------------------------

Consider the left side

cos²Θ - sin²Θ

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3 years ago
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