Answer:
Margin of Error = 5.4088 ;
Confidence interval = (30.1 ; 40.9)
Interval estimate are almost the same
Step-by-step explanation:
Given that :
Population standard deviation, σ = 9.3
Sample size, n = 8
Xbar = 35.5
Confidence level = 90%
The confidence interval:
Xbar ± Margin of error
Margin of Error = Zcritical * σ/sqrt(n)
Zcritical at 90% = 1.645
Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088
Confidence interval :
Xbar ± Margin of error
35.5 ± 5.4088
Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1
Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9
(30.1 ; 40.9)
T distribution =. (30.5 ; 40.5)
Normal distribution = (30.1, 40.9)
Answer:
the karla question. the answer is unfair
Step-by-step explanation:
because the multiple of 3 is 6
but there is no multiple of 4
so therefore it is not fair
<span>Conditional probability of b given a is given by dividing Probability of event b with the probability of both a and b occurring together. Hence in this case, conditional probability of b given a is 0.1 divided by 0.6. On division, the result that is obtained is 0.16.</span>
Answer:
x{#{@!
Step-by-step explanation:
