Answer:
candice
Step-by-step explanation: dic fit in yo mouth
To find the equation of a line that passes through the point (2, -3) with a slope m = -3.
1. We need to use the Point-Slope Form of the line. Then, we have:
![y-y_1=m(x-x_{1)}\Rightarrow y-(-3)=-3\cdot(x-2)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_%7B1%29%7D%5CRightarrow%20y-%28-3%29%3D-3%5Ccdot%28x-2%29)
In this equation, we have that:
x1 = 2, and y1 = -3
Then, solving the equation, we have:
![y+3=-3x+6\Rightarrow y=-3x+6-3\Rightarrow y=-3x+3_{}](https://tex.z-dn.net/?f=y%2B3%3D-3x%2B6%5CRightarrow%20y%3D-3x%2B6-3%5CRightarrow%20y%3D-3x%2B3_%7B%7D)
Therefore, the equation of the line in the <em>Slope-Intercept Form</em> is:
Answer:
AG = 16
Step-by-step explanation:
If you have a parallelogram, then the diagonals are bisected, meaning GS and SA are congruent, same with OS and ST. So, because 8 + 8 = 16, the length of AG = 16.
Answer: 10a^2 - 25 + 5b
Step-by-step explanation: Only you have to elevate all the numbers and expressions to the potence 2
Answer:
x = 2
Step-by-step explanation:
![\frac{24}{4x} = 3](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B4x%7D%20%3D%203)
24 = 3*4x
24 = 12x
24 / 12 = x
2 = x