To calculate amount accrued after a given period of time we use the compound interest formula: A= P(1+r/100)∧n where A i the amount, P is the principal amount, r is the rate of interest and n is the interest period.
In the first part; A= $ 675.54, r= 1.25% (compounded semi-annually) and n =22 ( 11 years ), hence, 675.54 = P( 1.0125)∧22
= 675.54= 1.314P
P= $ 514.109 , therefore the principal amount was $ 514 (to nearest dollar)
Part 2
principal amount (p)= $ 541, rate (r) = 1.2 % (compounded twice a year thus rate for one half will be 2.4/2) and the interest period (n)= 34 (17 years×2)
Amount= 541 (1.012)∧34
= 541 ×1.5
= $ 811.5
Therefore, the account balance after $ 811.5.
Answer:
IDK
Step-by-step explanation:
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Y=mx+b
First use the two point slope formula to find m
(y2-y1)/(x2-x1)
(2-0)/(-9-9)
2/-18
1/-9=m
Next use the point slope formula to find the answer
y-y1=m(x-x1)
y-0=1/-9(x-9)
Now use Distributive Property
y-0=1/-9(x)+1/-9(-9)
y-0=1/-9x+1
Your answer would be
y=-1/9x+1
