You take away the 4 from the 8 which is equal to 4 then you have to barrow from the 2 to make the 4 to 14 and when you wait you are basically right your calculation is right
Answer:
The area of the triangle is 18 square units.
Step-by-step explanation:
First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:
AB
![AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%285-2%29%5E%7B2%7D%2B%5B6-%28-1%29%5D%5E%7B2%7D%7D)

BC


AC
![AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%28-1-2%29%5E%7B2%7D%2B%5B4-%28-1%29%5D%5E%7B2%7D%7D)

Now we determine the area of the triangle by Heron's formula:
(1)
(2)
Where:
- Area of the triangle.
- Semiparameter.
If we know that
,
and
, then the area of the triangle is:


The area of the triangle is 18 square units.
First one is 7.73 (23.19/3)
Second one is 14.04 ((19.71/7.3) x 5.2)
Answer:
if this is a fraction, then negative 5 over a⁶
4/10 and 6/10
(40% and 60%)