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2 years ago

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A student constructs a regular square pyramid with a base that has sides of 13.2 cm and a slant height of 6 cm. Find the surface

area of the pyramid.
30 Points!!!!

1 answer:

Komok [63]2 years ago

6 0

Answer:

It is 409.72.

Step-by-step explanation:

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Please help me with question 2. What is the degree measure of the angle measure? Please show steps!

marshall27 [118]

Answer:

because of a geometry theorem since the angles have the same arc length they have the same angle measure

<u>20 degrees</u>

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2 years ago

The mapping diagram shows a function S(x).<br><br> Which mapping diagram shows the inverse of S(x)?

Nutka1998 [239]

<h3>Answer: Choice A</h3>

Explanation:

Notice how the input 5 leads to the output 3 when we look at the S(x) function. The inverse will undo this. So that must mean the answer is choice A where we have the input 3 lead to the output 5. In short, the inputs and outputs swap places. This means the domain and ranges swap.

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2 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

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2 years ago

Give the standard form for 900,000 + 50,000 + 9,000 + 600 +20+7

brilliants [131]

Answer:

nine-hundred thousand plus fifty thousand plus nine thousand plus six-hundred plus twenty plus seven

Step-by-step explanation: answer above

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2 years ago

Read 2 more answers

Of all rectangles with a perimeter of 12 which one has the maximum area

Vika [28.1K]

The rectangle maximum area will be A=9 square units with the length=3 and the width=3.

<h3>What is area of rectangle?</h3>

Area is defined as the space occupied by a plane or rectangle having length and width in two dimensional plane.

It is given that the perimeter of rectangle is P=12

So from the formula of perimeter of rectangle

2(L+W)=12

L+W=6

L=6-W

Now the area of rectangle will be

A=LxW

A=(6-W)W

Now for maximum area we will find the derivative and equate to zero.

$A=(6W-W^2})$

$A'=6-2W=0$

$W=3$

$L=6-W=6-3=3$

So the area will be

$A=3\times 3=9 \ square \ units$

Hence the rectangle maximum area will be A=9 square units with the length=3 and the width=3.

To know more about area of rectangle follow

brainly.com/question/25292087

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1 year ago