All categories

4 years ago

C=48y+0.99n solve for y

Mathematics

1 answer:

Ne4ueva [31]4 years ago

4 0

Answer:

y = (C -0.99n)/48

Step-by-step explanation:

Undo what is done to y, in the reverse order. We have y multiplied by 48 then added to 0.99n. So, we must add the opposite of 0.99n and multiply that result by the reciprocal of 48.

C = 48y + 0.99n . . . . . . given

C - 0.99n = 48y . . . . . . add -0.99n

(C -0.99n)/48 = y . . . . . multiply by 1/48

You might be interested in

Simplify: log base 3 (1/3) ...?

yarga [219]

The answer is 1.

$log_3( \frac{1}{3} )$
_____
Since $log_y(x) = \frac{log_{10}(x)}{log_{10}(y)}$ , then: $log_3( \frac{1}{3} )= \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)}$
_____
Since $\frac{1}{x} = x^{-1}$ , then: $\frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)} = \frac{log_{10}(3^{-1} )}{log_{10}(3)}$
_____
Since $log x^{a} =a*logx$ , then: $\frac{log_{10}(3^{-1} )}{log_{10}(3)}= \frac{-1*log_{10}(3)}{log_{10}(3)}$

From here: $\frac{-1*log_{10}(3)}{log_{10}(3)}=-1*\frac{log_{10}(3)}{log_{10}(3)}=-1*1 = -1$

6 0

3 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

In-s [12.5K]

Answer: t=-20ln(1/3)

Step-by-step explanation:

5 0

3 years ago

Find the measure of Angle 2. <br><br> measure of angle 1 = x<br> measure of angle 2 = x-6

marin [14]

Need more information or a graphic.

7 0

3 years ago

I WILL MARK BRAINLIEST WHAT DOES THIS MEAN????

bogdanovich [222]

Answer:

The answers are: 1 and 1.

Step-by-step explanation:

I believe they are how combinations are written. In other words:

$_{n}C_{r}=(\frac{n}{r})=n!/(r!(n-r)!)$ (Ignore the fraction bar, I can't really format it properly).

Anyways, simply find the combination of each:

$(\frac{9}{0})=9!/(0!(9-0)!)=9!/9!=1$

$(\frac{9}{9} )=9!/(9!(9-9)!)=9!/9!(0!)=9!/9!=1$

Note that 0! equals 1.

6 0

3 years ago

Read 2 more answers

Refer to the figure: The Triangle

deff fn [24]

Answer:

The Triangle Midsegment Theorem states that, if we connect the midpoints of any two sides of a triangle with a line segment, then that line segment satisfies the following two properties

Step-by-step explanation:

7 0

2 years ago