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Alexxandr [17]
3 years ago
9

A lamp post 15 feet high casts a shadow

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
Here you go! I decided to write it down for you. Sorry for the bad handwriting! :)

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8) The height of a building h varies directly as the length and inversely as the width, if h = 25m when l = 10m and w = 5m, find
shtirl [24]

Let h,l, and w represent the height, length, and width of the building respectively

Then

\begin{gathered} h\text{ = }\frac{kl}{w} \\ \text{where k is the constant of proportionality} \end{gathered}\begin{gathered} \Rightarrow k=\frac{hw}{l} \\ \Rightarrow k=\frac{25\times5}{10}=12.5 \end{gathered}\Rightarrow h=\frac{12.5l}{w}

The new value of h = 50m, but l remains the same.

That is l = 10m

Therefore

\begin{gathered} \frac{50}{1}=\frac{12.5\times10}{w} \\ \Rightarrow\frac{50}{1}=\frac{125}{w} \\ \text{Cross multiplying, we have} \\ 50w\text{ = 125} \\ \Rightarrow\text{ w=}\frac{125}{50}=2.5 \end{gathered}

Hence, the width is 2.5m

8 0
1 year ago
I JUST NEED #13 please and thnx
emmainna [20.7K]

\bf \cfrac{18}{32}\implies \cfrac{2\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 2}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{48}\implies \cfrac{3\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 3}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark

3 0
3 years ago
What system the system that is made up of the heart,blood, and blood vessels is called the ____ this is for sceince but i cant f
Fiesta28 [93]

Answer:

Cardiovascular system

Step-by-step explanation:

8 0
3 years ago
Aaron can paint a door in 6 h, and Ana can do the same job in 3 h. Working together, how many hours will it take them to paint a
Aloiza [94]

Answer:

4.5 hrs

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use the Distance Formula to find the distance between D(2, 0) and E(8, 6).
Mazyrski [523]

Answer:

The answer is

<h2>6 \sqrt{2}  \:  \:  \: or \:  \:  \: 8.50 \:  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question

The points are D(2, 0) and E(8, 6

The distance between them is

|DE|  =  \sqrt{ ({2 - 8})^{2}  +  ({0 - 6})^{2} }  \\  =  \sqrt{( { -  6})^{2}  + ( { - 6})^{2} }  \\  =  \sqrt{36 + 36}  \\  =  \sqrt{72}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 6 \sqrt{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\  = 8.4852813

We have the final answer as

6 \sqrt{2}  \:  \:  \: or \:  \:  \: 8.50 \:  \:  \:  \: units

Hope this helps you

5 0
3 years ago
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