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Alexxandr [17]
3 years ago
9

A lamp post 15 feet high casts a shadow

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
Here you go! I decided to write it down for you. Sorry for the bad handwriting! :)

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13
nata0808 [166]

Answer:

m = 5

a = -3

b = -15

Step-by-step explanation:

(m - 2) = 3 for x^2

(2a + 3) = - (m - 2) = (2 - m) for x^1

(b + 6) = (2a - 3) for x^0

4 0
3 years ago
Please answer my question I give thanks
dexar [7]
N is a variable
1. N+4
2. dk
3. N*5
4. N-7
5. N^2 (N squared) +1
6. 3-N^2
7. N^2÷6=42
8. 2×N+5=20
9. 4×N-7=32
10. dk
11. 10+N÷2=-15
12. dk
some of them might not be correct, i did my best. i am sorry. 

3 0
4 years ago
What is the slope of the line
serious [3.7K]

<em>he slope or gradient of a line is a number that describes both the direction and the steepness of the line. ... Slope is calculated by finding the ratio of the "vertical change" to the "horizontal change" between (any) two distinct points on a line.</em>

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6 0
3 years ago
Rewrite with absolute sign for -3
WITCHER [35]

Answer:

The absolute sign is 3

Step-by-step explanation:

The absolute sign is how far away a number is from zero. There are no negative signs when it comes to the absolute sign, it is always positive. -3 is 3 places away from zero.

7 0
3 years ago
140 subtracted from the square of a number the result is three times the number find the negative solution
natima [27]

Answer:

Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.

5 0
3 years ago
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