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3 years ago

The product of 5 and 3 less than 7

Mathematics

1 answer:

Delicious77 [7]3 years ago

8 0

-8

5*3=15

7-15=-8

i have to add charcters so i can post

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The sum of three consecutive integers is 915. what are the integers

ra1l [238]

(x-1)+x+(x+1)=915
3x=915
x=305

304, 305, 306

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3 years ago

Solve for x. 5 = 1/5x -3

Sav [38]

Answer:

40.

Step-by-step explanation:

5=1/5x-3

8=1/5x

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3 years ago

The apartment you like rents $700 a month. The landlord requires two months rent for the security deposit. How much is the secur

sergejj [24]

Answer:

$1400

Step-by-step explanation:

If a month of rent is $700 multiply that by 2 to get $1400

6 0

3 years ago

To the nearest whole percent, what is the probability that a randomly chosen member of the JV swim team does not wear glasses an

Yuri [45]

Answer: 14%

Step-by-step explanation:

Complete question is provided in the attachment below:

Probability that members of the junior varsity swim team wear glasses = 55%=0.55

Given: P(wear glasses) = 0.55

P(not wear glasses) = 1-0.55 = 0.45

P(member in 10th grade | not wear glasses) = 30%

Using conditional probability formula:

$P(B|A)=\dfrac{P(A\text{ and } B)}{P(A)}$

$\Rightarrow\ 0.30=\dfrac{P(\text{not wear glasses and in 10th grade})}{0.45}\\\\\Rightarrow\ P(\text{not wear glasses and in 10th grade})=0.45\times0.30\\\\0.135=13.5\%\approx14\%$

Hence, the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade = 14%.

So, the correct option is "14%".

4 0

3 years ago

The number of chocolate chips in an 18-ounce bag of Chips Ahoy! chocolate chip cookies is approximately normally distributed wit

sineoko [7]

Answer:

a) 0.013

b) 0.7

c) 0.866

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1262

Standard Deviation, σ = 118

We are given that the distribution of number of chocolate chips is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(fewer than 1000 chocolate chips)

P(x < 1000)

$P( x < 1000) = P( z < \displaystyle\frac{1000 - 1262}{118}) = P(z < -2.220)$

Calculation the value from standard normal z table, we have,

$P(x < 1000) = 0.013 = 1.3\%$

b) P(contains more than 1200 chocolate chips)

$P(x > 1200) = P(z > \displaystyle\frac{1200-1262}{118}) = P(z > -0.5254)\\\\P( z > -0.5254) = 1 - P(z \leq -0.5254)$

Calculating the value from the standard normal table we have,

$1 - 0.300 = 0.7 = 70\%\\P( x > 1200) = 0.7$

c)P(contains between 1000 and 1400 chocolate chips)

$P(1000 \leq x \leq 1400) = P(\displaystyle\frac{1000 - 1262}{118} \leq z \leq \displaystyle\frac{1400-1262}{118}) = P(-2.22 \leq z \leq 1.169)\\\\= P(z \leq 1.169) - P(z < -2.22)\\= 0.879 - 0.013 = 0.866 = 86.6\%$

$P(1000 \leq x \leq 1400) = 86.6\%$

6 0

3 years ago