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Montano1993 [528]
3 years ago
11

Write the equation of a line perpendicular to y=-5x that passes through the point (1,1) in slope intercept form. (This question

is worth 2 points. One point for the correct slope and the second point is for the correct y intercept.)
Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

y= 1/5x + 0.8

Step-by-step explanation:

Hope this helps

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what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base
JulsSmile [24]

Answer :

  • 301.44 cm³

⠀

Explanation :

We know,

{ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}

Where,

  • <em>r</em> is the radius of the cylinder. Here, the radius is 4 cm

  • <em>h</em> is the height of the cylinder. Here, height is 6 cm

  • Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \it{ \pmb{ Volume_{(cylinder)}  {= 301.44 \: }}}}}}

⠀

Therefore,

  • The volume of the cylinder is 301.44 cm³ approximately.
6 0
2 years ago
Read 2 more answers
Subtracted 3 form 5 , then multiply by one forth
Novay_Z [31]
I think -0.5
3-5= -2
-2x.25= -0.5
5 0
3 years ago
Read 2 more answers
2. Sam ran to the mall and back to quickly pick up a small
Aleonysh [2.5K]

Answer:

I think the answer is 47

Step-by-step explanation:

6 0
3 years ago
Choose an integer between -5 and -10. Label it ܴ on the number line created in Problem 3, and complete the following tasks.
qwelly [4]

Answer:

Your search - Choose an integer between -5 and -10. Label it ܴ on the number line created in Problem 3 ... - did not match any documents.

Suggestions:

Make sure all words are spelled correctly.

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Step-by-step explanation:

6 0
3 years ago
After releasing of radioactive material into.The atnosphere from.A nuclear.Powe plant in a country in 1988, the hay in that coun
Radda [10]

Answer:

the question is incomplete, so I looked for a similar one:

<em>After the release of radioactive material into the atmosphere  from a nuclear power plant, the hay was contaminated by iodine  131 ( half-life, 8 days). If it is all right to feed the hay to cows  when 10% of the iodine 131 remains, how long did the farmers  need to wait to use this hay? </em>

iodine's half life (we are given x, we need to find b):

0.5A₀ = A₀eᵇˣ

x = 8 days

we eliminate A₀ from both sides

0.5 = eᵇ⁸

ln 0.5 = ln eᵇ⁸

-0.69315 = b8

b = -0.69315 / 8 = -0.08664

since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):

0.1A₀ = A₀eᵇˣ

0.1 = eᵇˣ

ln 0.1 = bx

where b = -0.08664

x = ln 0.1 / -0.08664  = -2.302585 / -0.08664  = 26.58 days

4 0
3 years ago
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