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3 years ago

101 divided by 2 plus 4

Mathematics

2 answers:

kenny6666 [7]3 years ago

8 0

Answer:

54.5

Step-by-step explanation:

Bond [772]3 years ago

5 0

Answer:

54.5

Step-by-step explanation:

Hope this helps!! Do you need it in a fraction?

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DO NOT ANSWER QUESTION ONLY IF YOU WANT POINTS. ONLY ANSWER IF YOU ACTUALLY KNOW THE ANSWER!!!! question is in attached piture

Andre45 [30]

The probability of rolling that is 2/6 I think

4 0

3 years ago

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4 people stacked 40 pizzas . Ronnie stacked 0.25 of the pizzas and Mack stacked 9 outa the 40 and Kim stacked 35% so how many di

saw5 [17]

Answer:

Step-by-step explanation:

No. of pizza Ronnie stacked = 0.25 × 40

= 10

No. of pizza Mack stacked = 9

No. of pizza Kim stacked = $\frac{35}{100}$ × 40

= 14

No. of pizza Ada stacked = 40 - 10 - 9 - 14

= 7

3 0

3 years ago

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Metallic silver has a density of 10.50. what is the mass, in g, of a silver ingot that is 28.0 cm long, 4.90 cm wide, and 3.60 c

frozen [14]

Answer:

5190 g

Step-by-step explanation:

Calculate the volume:

28.0 cm × 4.90 cm × 3.60 cm = 493.92 cm³

Density is mass divided by volume:

D = M / V

Solving for mass:

M = D V

Substituting values:

M = (10.50 g/cm³) (493.92 cm³)

M = 5186.16 g

Rounding to three significant figures, the mass is 5190 g.

3 0

4 years ago

The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p

Juliette [100K]

Check the picture below.

based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,

$\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)$

$\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}$

now, we can plug those values on A = (1/2)bh,

$\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5$