According to the given information, segment UV is parallel to segment WZ, while angles SQU and VQT are vertical angles. Angle VQ
1 answer:
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Answer:
0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that ,
.
In this problem, we have that:
So
Probability that greater than 96 out of 153 DVDs will work correctly.
97 or more DVDs, which is 1 subtracted by the pvalue of Z when X = 97. So
has a pvalue of 0.6406
1 - 0.6406 = 0.3594
0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.
In this case you would set it up as
(180 represents the degree of the triangle)
Add up like terms
Subtract 130 to the other side (180-130)
Divide 10 to the other side ( 50/10)
.
Hope this was clear :)
(180 represents the degree of the triangle)
Add up like terms
Subtract 130 to the other side (180-130)
Divide 10 to the other side ( 50/10)
.
Hope this was clear :)