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Aleks04 [339]
4 years ago
15

According to the given information, segment UV is parallel to segment WZ, while angles SQU and VQT are vertical angles. Angle VQ

T is congruent to angle SQU by the Vertical Angles Theorem. Because angles SQU and WRS are corresponding angles, they are congruent according to the Corresponding Angles Theorem. Finally, angle VQT is congruent to angle WRS by the ________ Property.
Mathematics
1 answer:
erma4kov [3.2K]4 years ago
4 0

Answer:

Transitive

Step-by-step explanation:

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What is 3 to the sixth power times 3 there is a picture please help worth 12 pts.!!!!!
Diano4ka-milaya [45]

Answer:

2187 ( 3 to the 7th)

Step-by-step explanation:

3 to the 6th= 729

729 x 3 = 2187

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A manufacturer of a certain brand of appliance estimates that he can sell 5000 units a year at Php 900.00 each and that he can s
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Concept 44: I can determine the circumference of a circle and use the circumference of a circle to find its diameter and radius.
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3 years ago
If 3 is added to a certain number, the results is 15 less than three times the number. Find the number
Harman [31]

Answer:

number = 9

Step-by-step explanation:

number = x

3 is added to a number = (x+3) result

3 times the number = 3x

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8 0
3 years ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
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