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harina [27]
3 years ago
5

Which of the following is the solution to the system of equations shown below?

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

x = -2, x = 1

Step-by-step explanation:

mark as brainliest it is right

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Given the formula A = 5h (B + b); solve for B.<br> 2
stellarik [79]

Answer:

B = A/5h - b; You could use

B = (A - 5hb)/5h  This just puts everything over a common denominator.

Step-by-step explanation:

A = 5h (B + b)          Divide both sides by 5h

A/5h = B + b             Subtract b from both sides.

A/5h - b = B

6 0
3 years ago
What is the average rate of change of the function over the interval x = 0 to x = 6? f(x)=2x−1 3x+5 Enter your answer, as a frac
Tatiana [17]

Answer:

-11

Step-by-step explanation:

Our function is 2x-13x+5

  • 2x-13x+5= -11x+5
  • F(0)= 5 and F(6)= -11*6+5 = -61
  • let m be the average change : m= (-61-5)/6= -11

8 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
What is the value of r in (3r+4) °<br> (8r-2
lana66690 [7]

Answer:

r = 49

Step-by-step explanation:

8 0
3 years ago
Use the parabola tool to graph the quadratic function y=-1? - 2.0 +8
Andreas93 [3]

Answer:

see explanation

Step-by-step explanation:

I don't have graphing facilities but can give you the vertex and 1 other point.

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = - x² - 2x + 8 ← is in standard form

with a = - 1 and b = - 2 , then

x = - \frac{-2}{-2} = - 1

Substitute x = - 1 into the equation for corresponding value of y

y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9

vertex = (- 1, 9 )

To obtain another point substitute any value for x into the equation

x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph

x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0  then (2, 0 ) is a point on the graph

3 0
3 years ago
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